I just started learning linked list and nodes and I'm stil getting use to the syntax.
http://i1330.photobucket.com/albums/w575/academichusslepb/delete_node_zps61afd59b.jpg
I made this to help...
Type: Posts; User: c++noob145
I just started learning linked list and nodes and I'm stil getting use to the syntax.
http://i1330.photobucket.com/albums/w575/academichusslepb/delete_node_zps61afd59b.jpg
I made this to help...
say i have a list of numbers in an array created by a class template
#include <iostream>
#include <fstream>
#include <string>
#include <iomanip>
using namespace std;
#include <iostream>
#include <fstream>
#include <string>
#include <iomanip>
using namespace std;
const int CAPACITY = 5;
template <class T>
and Org is just the actual class object that is being passed through as a reference?
how do i copy from a dynamic array initialized in a class but with a different memory address
for example if my array is a dynamic array initialized in a class
const int CAPACITY=5;
...
ostream &
operator<<(ostream& output, Bank_Acct & Org)
{
output<<endl<<"Name "<<Org.name;
output<<endl<<"The balance is "<<Org.balance<<endl;
returnoutput;
}
I'm learning...
why can't << operator be overloaded as a member function is it because that is the way c++ is written and you just can't or is there another reason because I'm confused.
ok i have text file it has something like this
item1 5.00 7 no
item2 6.00 9 yes
item3 6.00 8 no
item4 5.00 7 no
and the list goes on
is it any different when using a class in my code
my previous code i define my struct like this
#include <iostream>
#include <fstream>
#include <string>
but it can the other way around
static_Array= dynamic_Array;
dynamic_Array = static_Array;
the second statement works and i'm able to print out both arrays with equal values
but with...
i'm still unclear between the difference between using pointer and a reference
I understood the concept of pointers in c in the class i took last year
and that was to change the actual value...
so let me get this clear
if (x == 0)
cout << "Run this program"<<endl;
cout <<"Run this too"<<endl;
Am I suppose to use curly braces in if statements
In my textbook it shows if statements without curly braces
like this
if(x=0)
cout<< x << "is 0" <<endl;
Hello everyone, I'm new to this board and fairly new to programming and I'm trying to understand some concepts on arrays so I'm trying to make this little program. I have a future assignment coming...