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I was working on my own approach. now I will check yours and learn and hopefully fix bugs and convert characters to numbers as well
thank you!

zero is not neglected anymore


if (n==0) {
printf("zero");
}

Thanks for lightening my mind after reading your comment it made perfect sense. for extra challenge, I put blanks after every 3 digit

#include<stdio.h>
#include<string.h>
#define d 9
#define e 9
#define f 4
int main()
{
char *num[]={"","one","two","three","four","five","six","seven","eight","nine"};
char...

#include<stdio.h>
#include<string.h>
#define a 9
#define b 9
#define c 3
int main()
{
char *num[]={"","one","two","three","four","five","six","seven","eight","nine"};
char...