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  1. Replies
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    I gave a proof sketch in my last post. The...

    I gave a proof sketch in my last post. The intuition is this:

    P(chosen-door) = 1/3
    P(host-door) = 0

    Thus,
    P(remaining-door) = 2/3.
  2. Replies
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    Here's another simulation that runs when your...

    Here's another simulation that runs when your browser loads. It also has an informal explanation of why 2/3 for a switch is correct.

    http://edp.org/monty.htm
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    CornedBee et. al. are correct. Mario, think of it...

    CornedBee et. al. are correct. Mario, think of it this way:

    The probability that you picked the right door first is 1/3 (I don't think there is any argument here). Thus, the probability that the...
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