I gave a proof sketch in my last post. The intuition is this:
P(chosen-door) = 1/3
P(host-door) = 0
Thus,
P(remaining-door) = 2/3.
Type: Posts; User: Perspective
I gave a proof sketch in my last post. The intuition is this:
P(chosen-door) = 1/3
P(host-door) = 0
Thus,
P(remaining-door) = 2/3.
Here's another simulation that runs when your browser loads. It also has an informal explanation of why 2/3 for a switch is correct.
http://edp.org/monty.htm
CornedBee et. al. are correct. Mario, think of it this way:
The probability that you picked the right door first is 1/3 (I don't think there is any argument here). Thus, the probability that the...