I got the idea.
this is interesting, I didn't know that. Thanks.
Type: Posts; User: thames
I got the idea.
this is interesting, I didn't know that. Thanks.
I knew about this warning, but I'd like to understand why, considering what I said, char (*argv)[50] wouldn't work. will that notation work in another function for what I wanted to print ?
edit: ...
Good afternoon. I was wondering why this program with a pointer for arrays with char (*argv)[100] doesn't work at all.
I understand char (*argv)[100] is declaring a pointer for arrays with n...