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For inputing 5 names ( i.e. 5 strings) you can use a 2-D character array , like


char nam[5][10]; // 5 names , each of maximum 10 chracters
int i;
for(i=0;i<5;i++)
{
printf("Enter nam[%d]...

I am a newbie to C-programming , so just making an effort to get into the logic of ur code.

char nam[5]; means we r declaring an array of 5 elements where each element is a single character OR a...

Oppss....That was a pathetic mistake i made..!!!:tongue:



Thankss Salem...It worked out beautifully for me...Thank u so so much...:redface:

I need to print the following series :

1-1/2+1/3-1/4......+-1/n

where n will be given by user.

I have written the code as :


int main()

int main(void)
{
int a[3][3]={{1,2,3},{5,6,7},{9,0,1}};
printf("\n\n Address of a[1]=%u",&a[1]);
printf("\n\n Value of a[1]=%u",a[1]);
printf("\n\n Element at a[1][0]=%d",*a[1]);
...

I am using Turbo C++ IDE . When I am using the following code :



int main(void)
{
int size=5,arr[size];

.......;
.......;

And I would have to say pls dont try to discourage ppl who want to share and learn C-programming with such out-of-context comments...I have just provided the code that I had felt might work for the...

/* Input 10 numbers in an array and count the number of occurence of an element inside the array */


#include<stdio.h>
#include<conio.h>

void main()

{

@Salem : True, main() always returns integer value.

What if I want a function not to return anything ?

Shud it not be preceede by the keyword void or add another statement : return(0);
...

Thank U Adak..Thanx soo much for the explanation and solution...U rock man..!! :o :redface:

Hi Adak, thnx for replying me.

Using a=tolower(a); cud have been used, but then i cudnt have printed :- The lower-case for A is : a

And yes, i wl definitely go by ur suggestion of using 'a'...

/*Toggle-Case : If lower-case character entered, then change to upper-case and vice-verse :*/


#include<stdio.h>
#include<conio.h>
#include<ctype.h>

void main()

{