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I kept going with my example, and this is what I came up with - I'm sure that you can get something out of this :)



#include <stdio.h>
#include <stddef.h>
#include <stdlib.h>


#define...

"pointer" is not an array -> it is a pointer.

Also, you can not do the following - It's like saying 4 = something


int *pointer;
int j;

for(j=0;j<size;j++)
&pointer[j] = &array[j+size];