And if you are confused why 1/i = -i, a simplified algebraic way of looking at it is
Knowing i^2 = -1, divide by sides by i and then
i^2/i = -1/i
i= -1/i
-i = 1/i
What clued me in into...
Type: Posts; User: SourceCode
And if you are confused why 1/i = -i, a simplified algebraic way of looking at it is
Knowing i^2 = -1, divide by sides by i and then
i^2/i = -1/i
i= -1/i
-i = 1/i
What clued me in into...
yea sorry typo, 1/i = -i
Your book is wrong.
x^(3/2) + 8x^(1/2) + 16x^(-1/2) = 0
has a solution at x = -4
Substituting -4 into the left side of equation we get
(-4)^(3/2) + 8*(-4)^(1/2) + 16*(-4)^(-1/2)