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I might have just fixed it by changing this line: [Items*new=(Items*)malloc(sizeof(Items*));} to



Items*new=(Items*)malloc(sizeof(Items));


Could someone explain how exactly my code is...

I changed the code slightly:

new->loc=&a[currentarea]; printf("%s", new->name);
new->prev=NULL; printf("%s", new->name);
new->next=NULL; printf("%s", new->name);


If the name is...

I don't really know how to even begin solving this problem. Basically, I have a structure:



struct Items{
char*desc;
char*name;
char*behave;
struct Areas*loc;
struct Items*next;

Laserlight is the best programmer in the whole world!

Wow! They both work, hm. I'm not even sure why new = malloc(sizeof(*new)); would work, how does it know what the size of new is supposed to be, if it doesn't know its an area*? I guess I don't really...

I added the following line to the end of the for loop



if(i>1){printf("[[::%p::]]", new->prev->prev);}


This shows that the pointer value is switching to ox11 at the end of each pass. But...

I created a series of linked lists and then printed them. Notice that I touch new->prev one time, and I verify it has been set via printf at the end of the for loop. However, when I then print all...

Oh, I don't think I need the while(1) at all, its just not necessary.

This is what I want:


void printnode(Area*current){
printf("\n<%d||[%p]>: <%p|%p>\n", current->name, current,...

break; was only there because return; wasn't working. I can take the break out but nothing changes.

void printnode(Area*current){
while(1){
if(current->next==NULL){printf("[%p]", current->next); return;}
if(current->next!=NULL){printnode(current->next);}
}
}


In this while loop, as I...

oh... that might be it actually... thanks! ill have to try and see if i can fix it now.

I have this section of code. Basically it uses fgets to read from a file, and at the end it does this:



new->name=name;
a[currentarea].items=new; ...

struct Areas{
char desc[255];
char name[255];
struct Items*items;
int n,s,w,e,u,d;
};


struct Items{
char*desc;

I don't know, I thought I have defined these structs. The error seems to be that it isn't properly defined. I tried what itCbitC said, but the following still gives the same errors:



typedef...

I'm trying to make this basic 'MUD' style game to practice coding, the problem I was having was trying to have two structure types, each of which can contain a pointer to the other type. After I...

Thanks! The following seems to work just fine:



printf("Number: %s\n", new->number);

It should look like this:

---------------Top of the Screen------------------


Enter Command:


Instead I get:

In input(), system("clear") executes first in a while loop, and then add(); is called... however, before add(); finishes and returns to input(), system("clear"); is called again and executes in the...

Oh, I think I know...

I need:

strcpy(new->name, input);


:D

Why might this be: incompatible types in assignment

Here is my struct:



typedef struct{
char name[250];
char number[10];
} List;

Obviously, I just did, which is why I said it seemed a lot easier -- how about we assume that if I see a line of code, I do try it -- and if I hear about a function, I probably go and look it up......

Oh, I was trying *X, *p[0], but going back to post #10 -- why use memcpy at all if I can just use what AndrewHunter suggested?

That seems a lot easier, why then would I ever want to use memcpy instead of that?

I did try it:


incompatible type for argument 1 of `memcpy'
incompatible type for argument 2 of `memcpy'

sizeof(p[0]) is 35024, is that the size of the structure regardless of the values within it, or do those change?


Should I just do:


memcpy ( X, p[0], sizeof(p[0]));
?

Yah I guess that...