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ok！thank you！

if don't use std::string ,how to write ?

#include <iostream>
using namespace std;
class String
{
public:
String(const char *str = NULL); // 通用构造函数
String(const String &another); // 拷贝构造函数
~ String(); // 析构函数
String& operator...

thank you for your answer. ihave correct it and test correctly.

#include<iostream>
using namespace std;
const int DefaultSize = 100;
class List
{
public:
List();
List(size_t size);
List(List &L);
~List();

ok ， that's the thing ，i correct it ，thank you ！

i just want to calculate the length of char*，so i write

int len(char* str)
{
int i = 0;
while (*str != "/0")
{
++i;
++str;
}

i just write a class below :

#include<iostream>
using namespace std;
const int DefaultSize = 100;
class List
{
public:
List();
List(size_t size);

who can explain ？ thank you

yes ， the template programming just can solve the question ！

that's right！ the size of the array should be included in the display function not compare with NULL， because the compile just take 0 as NULL， so when *t=0，the loop is over ，and you do twice...

i think in this easy program ， the easy syntax structure is enough ！

show your code maybe clear！

very good ！

it looks like C#

you can write like this ：

//Purse
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;

class Purse
{

you can clear the buffer in cin before input just like this ：

// print your name n times

#include <iostream>
#include <cstdlib>
#include <cstring>
#include <string>
using namespace std;

#include<iostream>
using namespace std;
class X
{
private:
int x;
public:
X():x(){};
void d(){cout<<x;};
void test(X p)

good ！