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A queue requires that the first element into the container be the first out out of the container, hence a queue needs to support both the push_back and pop_front functions. I believe that vector...

a queue cannot be built using the container vector because vector does not support pop_front.

can anyone verify the validity of this statment for me... or if this is not the main reason a queue...

yes, but i think it is more efficent to break out of the loop once it finds one card that doesn't have the same suit as the other ones because it cannot be a royal flush.

sorry for asking such a simple question, but i'm not too comfortable using break statements outside of switch.

Will the my break statement take me outside of the loop if the condition is true?
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