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I want him to enter
"text\n"
"text\n"
"text\n"
"\n" // type this to exit
3 // output if all 3 sentences are palindromes

#include <stdio.h>
#define MAX_INPUT_LENGTH 80

int is_palindrome(char []);

int main(void)
{
int i = 0, indicator = 0;
char words[MAX_INPUT_LENGTH] = {'a'};

Ok. I will keep that in mind.

oh no. no wonder! i thought 5%10=0!

Thanks a lot.

int sum_digits(int number)
{
int remainder, sum_int;

while(number!=0 && remainder!=0)
{
sum_int= sum_int+ number- number/10*10;
number= number/10;
remainder=sum_int%10;

ok i just started learning C and I only used the compiler gcc in ssh secure shell client to see the errors to debug or use the printf statement.

while (number > 9)
number = number % 9;

if (number == 0)
return (9);
return number;[/QUOTE]


Thanks it works much better!

* This program is designed to print a Fortune Cookie
* message for a positive integer entered by the user.

#include <stdio.h>

int sum_digits(int);
void print_cookie(int);

int main(void)...