Search:

> Yep, just point a double* to the base of the 8 byte char array and dereference it.
Better watch out for those alignment exceptions then, if such a pointer were to be mis-aligned for a double.

So long as your 8 bytes are in the correct byte order for the endian of your machine, then you can do


memcpy( &myDouble, mybuffer, sizeof(myDouble) );

But you're making a few assumptions by...