Search:

Have tried putting l=strlen(s);. Did not work out :(

Guys,

Have a very simple programme for finding the string length. But whats going wrong here.
[
#include<stdio.h>
#include<string.h>
#include<conio.h>
#include<stdlib.h>

main()

ohh sorry it works with ctrl+D. Thanks a lot...

Hi migf1,

There was a problem with permission. Now the above code works fine. if i end it with a dot. But when i removed and put EOF check condition it again does not work. The EOF for Linux is...

Hi migf1,

I have tried it again declaring ch as integer. Did not help. I have tried the below code provided by. the file myfile.txt gets created but i open it there is no content. whats going...

Hi,

Please tell why this programme does not work. I have an existing file file.txt. But the content does not get changed.



#include<stdio.h>
int main(){
FILE *fp;
char ch;

please help me in understanding these code snippets-

1)


int main ()
{
int a[2][2]={1,2,3,4};
a[1][0]=*(*(a+1)+1); // how this works??
a[1][1]=*(*(a+1)+0);

actually the Q has been asked in written test. and there was no option like compiler dependent. Anyway thanks for the reply...

Please help me in understanding this code snippet-



main()
{
int a=2,*f1,*f2;
f1=f2=&a;
*f2+=*f2+=a+=2.5;
printf("\n%d %d %d",a,*f1,*f2);

I have this code -



class A
{

public:
A(int a)
{

I have to test nos. whether it is prime or not between 1 to 30. What algorithm should i make use of???

How to find the value of z here

Int x = 5, y = 6, Z;
Z = x + + > (Z = - - Y)? Y + 2: ((x>z) ? x:y);

and why it prints 18 in the following programme-


int main()
{

can sumone help in understanding this piece of code-



main()
{
int (*functable[2])(char *format, ...) ={printf, scanf};
int i = 100;
(*functable[0])("%d", i);
...

Is it possible to overload the operator *+= such that
obj1 *+= obj2;
implies that
obj1=obj1*(obj1+obj2);

if i have a no. 895 and i have to print it in words i.e. eight nine five. i can make use of sprintf and get it printed. suppose i need to take user input for the no.and then get it printed in words...

What logic shud be used for swapping nibbles in a byte??

I am using turbo C++ IDE. and i included stdio.h

why the hell it prints 72


int main()
{
int i=0;
i=400*400/400;
printf("%d",i);
return(i);
}

how can i interchange every 2 bits in a byte like if 10 01 10 01 is input then output shud be 01 10 01 10. Please help me.

How the if condition works here?????????



void main()
{
int i;
char a[]="\0";
if(printf("%s\n",a))
printf("Ok here \n");

Thanks to both of you especially bithub for the comments...........................

Please help me in understanding the following code




main()
{
signed int bit=512, i=5;
for(;i;i--)
{

hello;

here is a piece of code-


main()
{
char *p1=“name”;
char *p2;
p2=(char*)malloc(20);

Basically wanted to ask about the use as embedded processor. I have nt heard about many projects using this. And what will be the future scope....

have anyone worked on rabbit processsor??????? exactly where it is used??? and about future scope????