Passing by reference
Doesn't require the address-of (&) operator when passing a variable
Doesn't require the dereference (*) operator when changing the value of a reference
Guarantees the...
Type: Posts; User: rudyman
Passing by reference
Doesn't require the address-of (&) operator when passing a variable
Doesn't require the dereference (*) operator when changing the value of a reference
Guarantees the...
Yeah. And the point I'm trying to make is, that feature is useless aside from syntactic sugar and it only causes ambiguity and misinterpretation. If the compiler didn't do that, it would see that the...
When I use GCC with Dev-C++, it gets interpreted as MyClass(*)(). Either way, the compiler changes the meaning of the code significantly (without telling you) from something that's semantically...
I think it's really stupid how the compiler turns a function name into a pointer to a function. It's for that reason that something like this gets misinterpreted as a function prototype instead of a...
AFAIK, changing a const variable results in undefined behavior and can only be done with unions, pointer arithmetic, const_cast, or placement new.
Mutable just means a member of a class/struct...
Also, unless there's more code that you haven't shown, you probably don't need virtual inheritance when deriving class amountnum. The virtual destructor is enough.
Yeah, choosing Palin was an attempt to win over some of Hillary's supporters. They sure are masters at what Obama would call silly politics.
Obama at least knows about Bubble Sort.
You have to use a lowercase 'm' in 'main':
int main()
{
...
The number 1 can be written as 0.999... just like it can be written as 1.000...
With that kind of mentality, it's almost like shorthand for a limit:
The difference between 1 and 0.99 is 0.01....
But without the union, how could you initialize the array and keep it encapsulated?
This is how I do it, at least:
class MyClass
{
public:
union
{
const int array [3]; // These both have the
You can also use unions to initialize arrays within classes/structs.
Yes.
For example,
union MyUnion { int n; double d; };
struct MyStruct { int n; double d; };
The union allows you to store an integer OR a double (but not both at the same time). The...
Hmm, but that might remove leading 0's.
You could return an array and have an (inline) function to print out that array. It may look obscure, unless you want to use dynamic memory:
// Edited out the solution.
Each language is good for different reasons. Java is the most popular, C is the fastest (typically), Ruby is probably the easiest and most expressive. It all depends on what you're looking for.
...
References "refer to objects", just like PHP references.
Pointers just store numeric memory addresses (which can even be 0, aka NULL), and you must use the dereference operator (*) and the...
By the way, ((U - L)/2) is the same thing as (U + L) / 2.
Or, better yet, (U + L) >> 1.
EDIT:
didn't realize they were doubles
If you want to prevent floating-point types, you can use template specialization:
template <typename T>
class My_Class
{
/* ... */
};
template <>
Your code looks logically correct, except you are not allocating memory for the second array (hence the seg fault). What you can do instead (in addition to laserlight's suggestion), is use a...
I have a class template with two parameters, the second of which is a template template parameter:
template <typename T, template <typename> class T2>
class Object
{
friend class Object...
Unfortunately, it's illegal to make a typedef for an incomplete type, like:
typedef std::vector MyVector; // Illegal!
Is there any kind of workaround for this without having to use macros?
Construction is a form of initialization, they help create objects of a class. It's actually a special function within the class.
Private data members make up the inner workings of a class. For...
From the looks of that error message, it seems you don't need the word 'new'.
Well, if you're passing by reference, the parameter will be an object (that is, it will already be constructed). You can't call the constructor on an object and probably shouldn't call the...