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I think you can use the c++ getch() with accepts a character without displaying it.

thanks Salem now i got a clearer picture of scanf.

char c;
while(scanf("%c\n",&c)==1 && c=='y')
printf("Hello");

//or

char c;
while(scanf("%c\n",&c), c=='y')
printf("Hello");

well you're defining the formal argument to the det function (i.e n) with the same name as the constant
you defined.
i.e #define n

all right here is the modified code but it still produces strange results. It doesn't work the first time you press y\n but the second time onwards it works



char c;...

the above code just goes through the loop once and does not ask for any more input.
now if i replace %c with %d and make that variable an int and do c==1 then the program works as desired.

hey I've just been using the comma operator and it is not producing the expected results



char c;

while(scanf("%c",&c),c=='y')
{
printf("Yes");
}

thanks for the replies. It's been real useful to know that float numbers are approximations and may give absurd results.

I had just been going through complex XORing to swap 2 variables without...

hey i am a complete newbie to c.


I am having this problem with floating points and the output is producing really wired results
I'm using gcc to compile it



float i=0.0;...