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OK, Cool; that works too, but I am still wodering why the other function doesn;t work. Is it becuase the array that is declard within the function is destroyed after the function exits?

for...

OK, I know it works, I jst want to know why.

OK, here is the deal, for examlpe I have a function:


void function(char s[]);

and I want it to take the character array as input and...