Hex String to a Long

I'm getting a hexadecimal input from the command line and I can't seem to get it to convert. I know, I know, use strtol(). The problem is I keep getting zero as the result. I hard-code hex strings ("0x13","0XF") and they work fine. I print out the string on the line before the conversion and it looks fine too.

strtol can absolutely do this, so perhaps if you post your code, we can figure out what is going wrong.

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Mats

Code:

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  result = GetFlag(nargs, args, 'S'); /* gets argument proceeding "-S" */
  fprintf(stdout, "seed=%u \n",seed); /* prints default seed value */
  fprintf(stdout, "result=%s \n",result); /* prints result string */
  if (result != NULL)
      seed = strtoul(result, NULL, 16); /* convert hex string to long */
  fprintf(stdout, "seed=%u \n",seed); /* comes back zero */

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result is a char*, and GetFlag returns a char*.

And what is the exact content of result (as per the printf)?

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Mats

I'm the dumbest man alive... on my console it's hard to tell the difference between a '0' and an 'O'. I've been preceeding the numbers with the letter O this whole time. I guess auto-complete isn't always a good thing.

Yup, that would of cours make a difference - and give the result you describe. Congrats to finding it - and I think you'll find that there are at least a few others who are equally dumb [and the dumbest may actually go to a lady I worked with who wondered why the copies didn't show up - turned out that if you copy what is on the back of a single-sided page, you get pretty much "nothing" :)]

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Mats