How To pass 2 dimensional array of strings to a function

Hello,
How To pass 2 dimensional array of strings to a function??at a go?
means i dont want to pass address of each string 1 by 1..but want to pass whole 2D array string at a go?

and ya those strings are local to main() not the global ones

Quote:

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Originally Posted by chottachatri

Hello,
How To pass 2 dimensional array of strings to a function??at a go?
means i dont want to pass address of each string 1 by 1..but want to pass whole 2D array string at a go?

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Maybe it's too early for me, but I don't see why you don't just pass the base address of the array, to the function.

What's this "pass address of each string 1 by 1", stuff about?

Would you show the relevant code in a post and surround it with the forum's code tags, please?

This is what i mean passing address of each string 1 by 1

Code:

---

#include <string.h>
#include <stdio.h>
void function(char *temp)
{
printf("&#37;s\n",temp);

}
void main()
{
int i,n;
char temp[10][30];
printf("\n\nHow Many Names Do You Want To Enter :");
scanf("%d",&n);
for(i=0;i<n;i++)
{
  printf("\n\nEnter Name ->%d :",i+1);
  flushall();
  gets(temp[i]);
}
for(i=0;i<n;i++)
{
 function(temp[i]);
}
getch();
}

---

Look at the above code each string is passed 1 by 1 in loop but i dont want to do that instead of loop i just want to pass the address a single time. How is it possible?

You might write the function as:

Code:

---

void print_strings(char arr[][30], size_t size)
{
    size_t i;
    for (i = 0; i < size; ++i)
    {
        printf("&#37;s\n", arr[i]);
    }
}

---

You would then call it as:

Code:

---

print_strings(temp, 10);

---

Incidentally, please read our wiki FAQ concerning void main and [url=http://cpwiki.sourceforge.net/Gets]gets[/man] to find out what is wrong with them. You should also indent your code better.

do this:

Code:

---

void func(char** names, n)
{
for (int i=0; i<n; i++) puts(names[i]);
}

// then call like this:
func(temp, n);

---

duh! laserlight is, fast like laser! fast like light! :D

probably becasu temp is declared as char temp[10][30]
print_strings should be declared as

Code:

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void print_strings(char arr[][30], size_t size);

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and not char**

PS. And i should be declared as size_t not int

Ok laserlight thank you very much! excellent! and ya i will use int main from now onwards

Quote:

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print_strings should be declared as

And i should be declared as size_t not int

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Indeed, I overlooked both, so I shall make the fixes.

Ok now can anybody tell me how to do the same job with integer array??i mean please can anybody give me code for that? i have done it by 1 method but anybody knows a sweet and short method for it then please tell me?

Code:

---


#include <stdio.h>
void print(int *a,int m,int n)
{
 int i,j;
 for(i=0;i<m;i++)
 {
  for(j=0;j<n;j++)
  {
    printf("&#37;d ",*(a+i*n+j));
  }
    printf("\n");
 }

}

int main(void)
{
 int a[3][3],i,k=1,j;
 for(i=0;i<3;i++)
 {
  for(j=0;j<3;j++)
  {
    a[i][j]=k++;
  }
 }
 print(&a[0][0],3,3);
 return 0;
}

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Also explain me the funtion of size_t i haven't come across that function :(

If you base your new code on my corrected example, you should have concluded that:

Code:

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void print(int *a,int m,int n)

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should be:

Code:

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void print(int a[][3],int m,int n)

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and that:

Code:

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print(&a[0][0],3,3);

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should be:

Code:

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print(a, 3, 3);

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Also, you can use a normal array subscript with a[i][j] instead of trying to compute the array index yourself.

By the way, I think that an indentation of just one space may be too little. Typically about four spaces would be optimal.

one dimention parameter is enough - second is hardcoded

Code:

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void print(int a[][3],int m)

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Quote:

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Originally Posted by manav

do this:

Code:

---

void func(char** names, n)
{
for (int i=0; i<n; i++) puts(names[i]);
}

// then call like this:
func(temp, n);

---

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A double pointer won't work as a replacement for a 2D array - it only works the other way around, that you can make a 2D array by using a double pointer. If you are going to use a double pointer, you will have to allocate "rows" number of pointers, then assign each pointer to the first element of the rows.

--
Mats

> but anybody knows a sweet and short method for it then please tell me?
Yeah, it's called copy and paste.

If this is your array,
int arr[2][3][4];

Then this is your function prototype
void func ( int arr[2][3][4] );


Yes, you can then fiddle with the prototype to change it into either of these forms, but you don't buy a lot. Some compilers will warn about the left-most dimension not being empty, but apart from that, it's good.
Alternatives:
void func ( int arr[][3][4] );
void func ( int (*arr)[3][4] );

Irrespective of the form you choose to write the function prototype / declaration, it would be called with
func ( arr );

And the usual array access subscripts you would use if the array were in scope will still do what you want inside the function.