Error proofing my switch statement.

Okay so I have a switch inside a loop and everything works fine and dandy until I enter a character into the switch. I realize that the switch is made on an integer, the problem is I figured the default case would take care of anything that wasn't one of the cases, but instead if a character is entered it goes into an infinate loop :(.

Here is my code:

Code:

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void Card_Game::play_game()
{
        //shuffle the deck first
        deck.shuffle_deck();
        //draw cards for players
        Linked_List<std::string> output_list;
        int gameloop = 1;
        int result = 0;
        int controller = 0;
       
        while (gameloop != 0)
        {
                IO::instance().clear_screen();
                switch(controller)
                {
                case 0:
                        // main menu
                        std::cout << "Welcome to the Casino!\n";
                        std::cout << "What would you like to do?\n";
                        std::cout << "1. Play Blackjack\n";
                        std::cout << "2. Quit\n";
                        result = IO::instance().get_input();
                        controller = main_menu(result);
                        if (controller == 3)
                        {
                                gameloop = 0;
                        }
                        break;
                case 1:
                        // blackjack function
                        std::cout << "What would you like to do?\n";
                        std::cout << "1. Draw a card\n";
                        std::cout << "2. Stay\n";
                        std::cout << "3. Fold\n";
                        result = IO::instance().get_input();
                        controller = blackjack(result);
                        break;
                case 2:
                        // deal again?
                        std::cout << "Would you like to deal again?\n";
                        std::cout << "1. Yes\n";
                        std::cout << "2. No\n";
                        result = IO::instance().get_input();
                        controller = deal_again(result);
                        break;
                }
        }
}

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What do I need to add to make it so if the user enters a character it doesn't break my switch? Or should I use a new form of input alltogether? Perhaps a character or string?

Quote:

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Originally Posted by Shamino

Okay so I have a switch inside a loop and everything works fine and dandy until I enter a character into the switch. I realize that the switch is made on an integer, the problem is I figured the default case would take care of anything that wasn't one of the cases, but instead if a character is entered it goes into an infinate loop :(.

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Where's your default case? I only see 0, 1 & 2.

Let me guess: IO::instance().get_input() reads an int, but if the user enters non-integral input, you get a failed read.

What you can do is alter the implementation of get_input() to check if the read succeeds. If it does not, it feedbacks to the user and requires the user to enter input again. At the same time it clears the error state of the stream (e.g., cin.clear() ) and discards the input (e.g., with cin.ignore() for a suitable number of characters). This can be done in a loop until the user enters integral input.

Quote:

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Originally Posted by cpjust

Where's your default case? I only see 0, 1 & 2.

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Sorry, yes the main loop has no default case because the switch on the controller variable is all internal and does not require user input. However menu selections do require user input so they need a default, the default switches are inside the functions run in the controller switch.

Laserlight I believe you've pretty much confined the problem to my get_input function, it does request integral data but if it does not get it the read does indeed fail.

How do I determine whether or not my read input is failed? I've never actually checked input like this.

Code:

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int IO::get_input()
{
        std::cin >> input;
        return input;
}

---

Code:

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int IO::get_input()
{
    // assuming input is a member variable...
    while (!(std::cin >> input))
    {
        // clear error flags
        // ignore what remains in the input buffer
        // optionally, ask user to enter input again
    }
    return input;
}

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Thanks very much, that cleared up the problem just fine.

I have another question though, is there a way to not use windows functions but still get keyboard events? Like the up arrow key and down arroy key in a console window?

Controller never gets reset if it gets set to an invalid value. The first time a bad value goes in, you go into an infinite loop. You need a default case which breaks the outer loop.

Controller should never get a bad value unless I program something wrong, the variable controller is controlled internally, whereas the functions I perform to set controller have switches in them that require user input, which can be error prone. I guess I should have showed you the functions themselves rather than the main event loop. Basically controller getting a bad value would be only due to programmer fault and not the user themselves.

The functions being used to control the controller variable are the ones getting bad values, but that was due to the get_input function not checking for bad input.

I have a question, whenever I get some bad input, and i request input again, it makes me input it twice, how do I prevent this from happening?

Quote:

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Originally Posted by Shamino

Controller should never get a bad value unless I program something wrong, the variable controller is controlled internally, whereas the functions I perform to set controller have switches in them that require user input, which can be error prone. I guess I should have showed you the functions themselves rather than the main event loop. Basically controller getting a bad value would be only due to programmer fault and not the user themselves.

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But code goes wrong all the time :) Why not just make it bullet proof?

Quote:

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Originally Posted by Shamino

I have a question, whenever I get some bad input, and i request input again, it makes me input it twice, how do I prevent this from happening?

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This sounds like that standard "not flushing stdin" problem. It's in the FAQ.

oh, I was flushing it, I was just adding another cin call that was unneeded, bahah.