Reference are always lvalue?

Hello everyone,


Is the conclusion correct? Both const reference and non-const reference are lvalue?

I think it is true and I can not find a sample which does not follow it.


thanks in advance,
George

For all intents and purposes, yes. (From a language lawyer standpoint, I think references are actually neither, but can always be converted to lvalues.)

Thanks CornedBee,


Could you provide more description please what do you mean below?

*I think references are actually neither, but can always be converted to lvalues*?

Quote:

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Originally Posted by CornedBee

For all intents and purposes, yes. (From a language lawyer standpoint, I think references are actually neither, but can always be converted to lvalues.)

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regards,
George

No, I can't. I'm too lazy to look up the wording of the standard, and it doesn't matter.

Well CornedBee, it is ok. I assume all references -- non-const and const reference -- are both lvalues. :-)

Quote:

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Originally Posted by CornedBee

No, I can't. I'm too lazy to look up the wording of the standard, and it doesn't matter.

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regards,
George