convert time_t to char*

hey,

i want to convert a time_t = time(NULL); timestamp to a char*.

What would be the best way to do that?

Thank you
Lennart

http://www.cplusplus.com/reference/c...e/asctime.html

Simplest form is ctime (and friends). More flexible, but also more complex to use, is strftime().

http://www.hmug.org/man/3/ctime.php

http://www.hmug.org/man/3/strftime.php

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Mats

thank you.

but i just want to get the timestamp as a string - not a formatted, human readable time

How do you mean? It's either in binary form, or it's in a character array - the latter will be more or less human readable.

Of course, if you really just want it as something that is ASCII, but not human readable, something along these lines would do it:

Code:

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char *time_t_2_ascii(const time_t time)
{
    size_t i;
    char *str = malloc(sizeof(time_t) * 2 + 1);
    unsigned char *ptr = (unsigned char *)&time;
    for(i = 0; i < sizeof(time_t); i++) {
      sprintf(&str[i*2], "%02x", ptr);
      ptr++;
    }
    return str;
}

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Mats

Quote:

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Originally Posted by crisis

thank you.

but i just want to get the timestamp as a string - not a formatted, human readable time

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You mean convert the NUMBER to a string representing that number? Just run it through stringstream:

Code:

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std::string time_t_to_string(time_t t)
{
    std::stringstream sstr;
    sstr << t;
    return sstr.str();
}

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