overloading operators

Code:

---

class String
{
  protected:
    std::string string;
  public:
    String operator= (char *str);
}

String String::operator= (char *str)
{
    string = str;
}

---

I want this to function like the string class that when you create a string you can assign a char pointer to it.

For instance, I want to be able to do:

Code:

---

String s;
s = "Hello, world!";

---

However, when I try to run that my program crashes. Is there something I'm doing wrong?

you dont get any warnings after compiling? do you have to change the parameter to 'const char *str'? if that doesnt help could you post the complete code so i can try it?

Did you #include <string>?
I couldn't even get the code to compile.

Operator= should return a String reference, using the this pointer.

I included <string>

Here is everything you should need that I have:

Code:

---

class String
{
  protected:
        std::string string;

  public:
        String operator= (char *str);
};

String String::operator= (char *str)
{
        string = str;
}

int main(int argc, char *argv[])
{
        String s;
        s = "Hello, World!";
        return 0;
}

---

your problem is solved by doing what MacNilly suggested stated

He said I should include <string> and I did.

"Operator= should return a String reference, using the this pointer."

I'm not entirely sure what that means or what I should do with it.

I just want to be able to set the std::string inside of the String class equal to a value as a regular std::string can. Am I on the right track and if MacNilly told me how to fix it. I don't really understand.

Sorry, but could someone elaborate a little.

Thank you.

he said you should return 'this' from your operator= function, just like how you 'return 0' in main, but 'this' instead of '0'. in doing so, you have to change the return type (from String) so that it returns a pointer to a string, so change it to String*.

hopefully you can get it!

That works, but I don't understand the logic at all. I would really like to overload a lot of operators in the program I'm working on right now. So, if anyone could explain how this works or direct me to a good article about this that would be great.

I searched google, but I didn't really get anything direct.

Code:

---

your_String = "static string literal";

---

Is the same as

Code:

---

your_String.operator=("static string literal");

---

Now, if you have

Code:

---

my_String = your_String = "static string literal";

---

Then you really have

Code:

---

my_String.copy_constructor(your_String.operator=("static string literal"));

---

The only argument the default copy constructor takes is a reference to an object of the class's type (String). So, have your operator=() function return a reference to a String. Which String? Well, which object does it make sense to return? this object. So, we return *this (the actual object calling the operator), for which a reference to is returned by the function.

Why wrap a class around just a std::string object, when you can just use a std::string object? I really don't see the point!

Because I'm using it to render strings. And if I wouldn't have the class you would have to have a function with 4 arguments instead of string.draw(x, y);

It still seems a bit dubious that you'd need to reimplement a lot of std::string functionality to render it. Shouldn't you be able to do draw(string, x, y)?

Other than that, is a function with 4 arguments that bad? You could also reduce the number of arguments by packing x and y into a Point struct. (draw(string, place, colour) for example)

Right. But then I would have to have the font rendering strings. Instead of the strings rendering themselves. Which wouldn't be so bad if my engine wasn't set up differently. And if I did that I wouldn't be able to build the texture for the string before hand if it was a constant string.