hi all(function problem )

hi all i am new here
straight to the point
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Code:

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#include<stdio.h>



void ekleme( int *s, int *t )
{
        while('\0' != *s)
  {
    ++s;
  }
 
    while('\0' != (*s = *t)){
    ++s;
    ++t;
  }

}
 







main(){
     
    int a; 
    int b=0,c=0;
     
    char string1[1000],string2[1000]; 
     
      while((a=getchar()) !=EOF)
            string1[b++]=a;
         
            string1[b]=0;       
     
     
        while((a=getchar()) !=EOF)
            string2[c++]=a;
         
          string2[c]=0;
     
     
  void ekleme( int *string1, int *string2 );
     
      printf("%s",string1);
   
     
      getchar();
      return 0;
      }

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this is my source code
it is a program to copy the string2 to the end of string 1 by calling ekleme routine with pointers

In the book i study c programming i can solve every problem so far without calling functions in main including this one but not with functions like ekleme

i think i am doing something wrong here with the function but what?

i would be grateful if someone can explain
thanks

p.s. compiler gives me error messages if i dont use
void ekleme( int *string1, int *string2 );
in everywhere why is that?

void ekleme( int *string1, int *string2 );
is function prototype not function call

function call will be

ekleme( string1, string2 );

[Warning] passing arg 1 of `ekleme' from incompatible pointer type
i get this warning when i do it and it still doesn t work properly

it is the same
just prints the string1 as it is in the beginning...

prototype of ekleme (why not myStrCat?) should be

void ekleme(char* dst, const char * src);

You have problems with entering 2 strings... After stdio receives EOF it cannot give you any char without resetting the error flag

Maybe - better to stop on \n? or even use fgets instead of loop?

You have problems with entering 2 strings... After stdio receives EOF it cannot give you any char without resetting the error flag

but i tested that
both of the strings are there when i say printf string 2 or 1

void ekleme(char* dst, const char * src); why constant char?

hi again

i get the code to work but only when i do the following:
1-compile and run
2-write something on keyboard for string1
3-press Enter twice but why?
4-put EOF character
5-press enter once
6-write something on keyboard for string2
7-press Enter twice
8-put EOF character
9-press enter

voila!!
string2 is copied to the end of string1

only on one of the step 3 and 7 you have to press Enter twice

does this have something to do with getchar()?
and how do i get input from keyboard to assign arrays by any other way


thanks

i have another function problem
any help would be good

Code:

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#include<stdio.h>
#include<ctype.h>

int i,d;
void rever(char string1[],char string2[])
{
    extern int d,i;

    string2[i++]=string1[d--];   
   
      if(d>=0)
/*12.line*/    rever( string1[],string2[]);
   
    }





main(){
      extern int d,i;
      int a,b,c;
      extern char string1[1000],string2[1000];
     
     
      a=0;
      while((b=getchar()) !=EOF)
            string1[a++]=b;
         
            string2[a]=0;
     
      d=a-1;
      i=0;
 /*34. line*/    rever(string1[],string2[]);
      string2[i]=0;
     
     
      printf("%s",string2);
     
   
     
      getchar();
      return 0;
      }

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i get this error as usual

syntax error before ']' token
line 12 and 34(both lines when i call rever() function)
i always get this but why?

again any help at all will be appriciated

Quote:

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Originally Posted by benhaldor

syntax error before ']' token
line 12 and 34(both lines when i call rever() function)
i always get this but why?

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Its a syntax error. just as the compiler tells.
Try

Code:

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rever( string1,string2);

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Kurt

yeah thanks zuk

actually i figured it out by myself before you posted but thanks anyway