Overriding

Suppose I have class in a library whose method i wish to override, but it is not declared virtual

How can I go about overriding the method?

all methods in Java are virtual so, no such problem occurs there

C# provides an explicit new keyword for the same problem

I expect C++ didnt had that feature... but still ready to for a strange answer

I don't believe that you can do this.

Though if you have a child object and call foo(), it will call the child object's foo function even if the parent class has an equivalent foo function defined.

The problem you'll run in to is that if you have a pointer to a base class that points to a child class, calling foo will always call the base class's implementation.

Quote:

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Originally Posted by jverkoey

The problem you'll run in to is that if you have a pointer to a base class that points to a child class, calling foo will always call the base class's implementation.

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yeah, bcoz it was never overriden!

So there you go.

You can override any base function, but if it's not virtual, then you won't have polymorphism, however you can make a buffer class, for instance:

Code:

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#include <iostream>
#include <string>


class base
{
public:
    std::string somenonvirtualfunction()
    {
          return "Base";
    }
};

class newbase : public base
{
public:
    virtual std::string somenonvirtualfunction()
    {
          return base::somenonvirtualfunction();
    }
};

class derived : public newbase
{
public:
    virtual std::string somenonvirtualfunction()
    {
          return "Derived";
    }
};
int main()
{
newbase* a = new newbase;
newbase* b = new derived;

std::cout << a->somenonvirtualfunction() << "\n";
std::cout << b->somenonvirtualfunction() << "\n";

}

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