Array and Pointers

Hi All.
I was trying to compile this program....but it was not compiling.
Can any one help..

Code:

---

#include<iostream.h>

void display(int *a,int row,int col){
                        int i,j;
                        for(i=0;i<row;i++)
                        {
                                cout<<"\n";
                                for(j=0;j<col;j++)
                                        {
                                                cout<<" "<<*(a+i*col+j);
                                                  }
                                  }
                }

void main(){
        int a[3][2]={
                        {1,5},
                        {3 ,2},
                        {1,4},
                        };
        int i,j;
        display(a,3,2);
        getch();
    }

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first, when you have compile errors, post them.

- change 'iostream.h' to 'iostream'
- add 'using namespace std;' after the include statement
- in your function 'display', 'a' is an array so in your last cout statement i imagine you want a[i]
- 'void main' should be 'int main'
- i think if you use 'getch' you have to '#include <ncurses>'

What's the point of indenting if you do it at random?

Quote:

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Originally Posted by nadroj

first, when you have compile errors, post them.

- change 'iostream.h' to 'iostream'
- add 'using namespace std;' after the include statement
- in your function 'display', 'a' is an array so in your last cout statement i imagine you want a[i]
- 'void main' should be 'int main'
- i think if you use 'getch' you have to '#include <ncurses>'

---

The error coming while compiling is
1) cannot convert ' int [2] * ' to ' int * '
2) Type mismatch in parameter a in call to display

Yes, in int main() a is declared as a two-dimensional array, which needs to be passed to a function that accepts a pointer to a pointer.

I suppose, if the array is declared statically as you do, it's still a contiguous block of memory, and you can also pass the first pointer (a[0]).

Quote:

---

Originally Posted by anon

Yes, in int main() a is declared as a two-dimensional array, which needs to be passed to a function that accepts a pointer to a pointer.

I suppose, if the array is declared statically as you do, it's still a contiguous block of memory, and you can also pass the first pointer (a[0]).

---

Thanks for your response.
It worked with display(a[0],row, col)

I was wondering if there is any other way to do this except this a[0] way......

&a[0][0] would also work.

Hand sub-scripting a 2D array is on the margins.
http://c-faq.com/aryptr/ary2dfunc2.html