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I am very new to the programming world and I am taking C Language programming and I am having trouble with an assignment. This is the assignment....
I am not asking how to do the entire assignment, but rather one part. I don't know how to get the desired names to display with the sales. I can get it so the program will display 1-5 where the names should be, but I don't know how to display the names as in the example.Quote:
Originally Posted by homework
your patience is greatly appreciated.
leo
sorry for the crappy post. i have never posted on here
Well, the code tags preserved the formatting. For long quotes, use quote tags.
Anyway, without reading all of the fine print of the assignment, I would still have to conclude that it contains a lot of details. What you should be doing is working slowly on it.
Can you state the problem to yourself in simple English or some other eqivalent natural language? Do you intuitively understand the solution to the assignment? If you can answer yes to both of those questions, then on paper or in a simple text editor, try explicitly writing down every single step of your solution.
After you have done all of this, translate the above solution into C.
Some of this is already taken care of. They tell you the exact functions to write and what the functions should do. This means you just have to pay attention to their details.
Lastly, unless you demonstrate that you put forth effort, you are not likely to be helped, and in fact, quite likely to be flamed. :)
Somehow I think you're having trouble with more than this. If you're using printf() to display your information, then use %s in place of the names, and pass the names of the arrays. For example, if you have all of your names of the employees in an array called names and their salaries in an array called salaries, then perhaps the following would work:Quote:
I am not asking how to do the entire assignment, but rather one part. I don't know how to get the desired names to display with the sales. I can get it so the program will display 1-5 where the names should be, but I don't know how to display the names as in the example.
This is only a demonstration of an idea of how it could work. You should write your own code and post it.Code:for(i=0;i<5;i++)
{
printf("%s %d\n",names[i],salaries[i]);
}
You could have a char array containing the names and save them in the same order and it should be rather easy to print the names.
this is what i have at the moment. Is this the right idea? more to come...
Code:#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
#include <string.h>
/*=========================Functions=========================*/
void main( );
void report( );
void getaverage( );
double getchoice(double ch);
/*==============================================================*/
void main( )
{
double totalsales[40];
char realnames[6][6] = {"Larry", "Sue", "Eva", "Morley", "Pete"};
double totsale;
double avgsale;
double ch;
printf("\n\t\tRocklin Realty\n\n\n");
getchoice(ch);
printf("%s\n%s\n%s\n%s\n%s\n%s\n", realnames[0],realnames[1],realnames[2],realnames[3],realnames[4],realnames[5]);
return;
}
/*==============================================================*/
double getchoice(double ch)
{
printf("Please enter your code:");
scanf("%lf%*c", ch);
return (ch);
}
/*==============================================================*/
/*==============================================================*/
/*==============================================================*/
void report( )
{
}
/*==============================================================*/
void getaverage( )
{
}
void main() is not the right idea. ;) It's non-standard. You should be using int main(), no matter what your teacher says. See the FAQ.
You're missing a &. Also, do you really want to be using a double?Code:scanf("%lf%*c", ch);
#5
I dont think you want to store numbers in a char array
Here is my latest. I appreciate your help. Now i must go to work. be back later
Code:#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
#include <string.h>
/*=========================Functions=========================*/
int main( );
void report( );
void getaverage( );
double getchoice(double ch);
double getsales(double sale[20]);
int getyn(char msg[]);
/*==============================================================*/
int main( )
{
double totalsales[40];
char realnames[6][7] = {"Larry", "Sue", "Eva", "Morley", "Pete"};
double totsale;
double avgsale;
double ch, money;
int choice, sale, i;
do
{
printf("\n\t\tRocklin Realty\n\n\n");
getchoice(ch);
getsales(sale);
totalsales[sale];
for (i = 0; i <5; i++)
printf("%s %.2lf\n", realnames[i], totalsales[i]);
choice = getyn("\nAnother");
}
while (choice != 'N');
return 0;
}
/*==============================================================*/
double getchoice(double ch)
{
printf("Please enter your code:");
scanf("%lf%*c", &ch);
return (ch);
}
/*==============================================================*/
double getsales(double sale[20])
{
double dollar;
printf("Please enter your sale:");
scanf("%lf%*c", &dollar);
return (dollar);
}
/*==============================================================*/
/*==============================================================*/
void report( )
{
}
/*==============================================================*/
void getaverage( )
{
}
/*==============================================================*/
int getyn(char msg[])
{
int c;
printf("%s (Y/N):", msg);
c = getchar();
c = toupper(c);
return c;
}
/*==============================================================*/
Not bad; but you call this function
like this:Code:double getchoice(double ch)
{
printf("Please enter your code:");
scanf("%lf%*c", &ch);
return (ch);
}
I think you should either get rid of the parameter, return the value, and same the result (don't discard the return value); or pass the variable as a pointer.Code:getchoice(ch);
Also, this line doesn't do anything:
(And sale is uninitialized because the call to getsales() doesn't modify it; also, it is the wrong type for getsales().)Code:totalsales[sale];
You only need to prototype main() for really old, non-standard compilers.
I suggest you turn on warnings. Add these options to GCC:
Code:-W -Wall -ansi -pedantic
I have been working on this program for the last three days and yesterday I some great help from this site. Thank you to those that helped me. But I have run into another brick wall.
Here is my current code. I have the display that I want, but I can't seem to get the sales that I input to go to the names in the display. Note: the function getaverage is still in the works.
PHP Code:#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
#include <string.h>
#define SIZE 6
/*======================================================*/
int getyn(char *msg);
int getcode(int *code);
double getsales(double *money );
void error(void);
void initcosts(char *ary);
void report(char ary[][7], double constant);
/*======================================================*/
/*======================================================*/
int main(void )
{
char name[6][7] = {"Larry", "Sue ", "Eva ", "Morley", "Pete"};
double totsales[6];
double sale, tot, avg;
int code, choice;
//initcosts(totsales);
do
{
printf("\n\t\tRocklin Realty\n\n\n");
code = getcode(name);
sale = getsales(totsales);
name[code][6] += sale;
choice = getyn("\nAnother");
tot += sale;
avg = (tot / 5);
}
while (choice != 'N');
printf("%.2lf\n\n", sale); // To check to see if it is printing the right amount
report(name, *totsales);
printf("\nTotal:%.2lf", totsales);
printf("\nAverage:%.2lf", avg);
return 0;
}
/*======================================================*/
/*======================================================*/
void getaverage(double *totsales, double *tot )
{
return;
}
/*======================================================*/
int getcode(int *code)
{
int key, err;
do
{
printf("\nPlease enter your code:");
scanf("%d%*c", &key);
err = (key < 1) || (key > 5);
if (err) error();
}
while (err);
return (key);
}
/*======================================================*/
double getsales(double *money )
{
double dollar;
printf("Please enter your sale:");
scanf("%lf%*c", &dollar);
return (dollar);
}
/*======================================================*/
int getyn(char *msg)
{
int c;
printf("%s (Y/N):", msg);
c = getchar( );
c = toupper(c);
return c;
}
/*======================================================*/
void error(void)
{
printf("\n\tYour code is invalid\n");
printf("\tPlease try another code");
return;
}
/*======================================================*/
void initcosts(char *ary)
{
int i;
for (i = 1; i < 6; i++ )
ary[i] = 0;
}
/*======================================================*/
void report(char ary[][7], double constant)
{
int i;
printf("Realtor\t\t\t\t\tTotal Sales\n\n");
for (i = 0; i < 5; i++)
{
printf("%s\t\t%22.2lf\n", ary[i], i);
}
}
/*======================================================*/
/*======================================================*/
Thank for the help it is greatly appreciated.
If you want to colour code use codeform (with the default options) instead of PHP tags: http://dwks.theprogrammingsite.com/m...e/cfonline.htm
Doesn't this sample look better?
Or in Dev-C++ style:Code:totalsales[sale];
/*======================================================*/
/*======================================================*/
int main(void )
{
char name[6][7] = {"Larry", "Sue ", "Eva ", "Morley", "Pete"};
double totsales[6];
double sale, tot, avg;
int code, choice;
//initcosts(totsales);
do
{
printf("\n\t\tRocklin Realty\n\n\n");
(Don't listen to me, I wrote codeform. :D )Code:totalsales[sale];
/*======================================================*/
/*======================================================*/
int main(void )
{
char name[6][7] = {"Larry", "Sue ", "Eva ", "Morley", "Pete"};
double totsales[6];
double sale, tot, avg;
int code, choice;
//initcosts(totsales);
do
{
printf("\n\t\tRocklin Realty\n\n\n");
return statements in void functions are optional.
You're not calling get_code properly.
I'll expand on "You're not calling get_code properly." get_code(), as you can see, takes an int* for an argument:
But you're calling it with a char**:Code:/*======================================================*/
int getcode(int *code)
{
int key, err;
do
{
printf("\nPlease enter your code:");
scanf("%d%*c", &key);
err = (key < 1) || (key > 5);
if (err) error();
}
while (err);
return (key);
}
Why don't you just leave out that parameter? You're not using it.Code:char name[6][7] = {"Larry", "Sue ", "Eva ", "Morley", "Pete"};
// ...
code = getcode(name);
I am not sure how I am supposed to call get_code. And do you mean here
Now is this because it is a pointer?Code:code = getcode(name);
So do I need to have it like:
Code:code = getcode(*name);
oh ok maybe i should have read your last reply before posting my last
No, no. getcode() takes an int*, so maybe you'd want to pass itQuote:
Originally Posted by leopardforest@g
or something; but since you never use the parameter, why not get rid of it?Code:code = getcode(&code);
Unless you have to use that prototype. In that case, don't return code; instead, use the code passed as a parameter.