start a program with space in the path

How do I start a program from a C program whose path is has a space in it?

For example, lots of applications are installed in C:\Program Files\...,

I've tried "system()", but it thinks "C:\Program" is the command name,

The "spawn" functions don't like the space in the path either.

Thanks,

Perhaps they don't like the \P?

Post your code.

Use forward slashes in string literals if you prefer, otherwise escape a backslash with a backslash.

Enclose the whole string within double-quotes (which each may need to be escaped if used in a string literal).

The line is: _spawnl(_P_WAIT, CL, CL, buffer, NULL);

If CL is "c:\devstudio\vc98\bin\cl.exe", the spawnl() works. (VC is not installed in the default directory.)

If CL is "c:\Program Files\Microsoft Visual Studio\VC98\bin\cl.exe", then spawnl() won't work.

The "buffer" contains the rest of the parameters.

Actual code really does help.

But does this work?

Code:

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""c:\Program Files\Microsoft Visual Studio\VC98\bin\cl.exe""

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nope. :-(

Tried it before I posted.

Use "" only for argv[0]. Following is working:

Code:

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int main(int arc, char* argv[])
{
        char CL[] = "d:\\1 1\\N.EXE";
        char CL2[] = "\"d:\\1 1\\N.EXE\"";
        _spawnl(_P_WAIT, CL, CL2, 0);
        return 0;
}

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For system() Dave_Sinklula's solution should work, though.

Code:

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system("\"\\program files\\mozilla firefox\\firefox\"");

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Alternatively, use the DOS name for the folder.

Code:

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system("\\progra~1\\mozill~1\\firefox");

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