Find '&' character in char array?

I need to loop through a char array containing a line read by fgets and check for the '&' character. I thought that fgetc or getc might do the trick, but it seems that they can only recieve a FILE *stream, not an array. This is what i tried:

Code:

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void run (char cur[]) {
    char c;
    char flag;
    c = fgetc(cur); // or getc
    while(c != EOF){
        if(c == '&') {
            printf("you wrote & char\n");
            flag = 'y';
        } else {
            printf("you didn't write the & char\n");
        }
    }

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"Passing arg 1 of 'fgetc' from incompatible pointer type."

Assuming cur is NULL terimated, just run through a loop from 0 to < strlen(cur) checking each character in cur against '&'.

If cur isn't NULL terminated, then you'd also need to know the number of chars in cur.

Why not just something like

Code:

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for(int n=0;n<length;n++)
{
  if(arr[n] == '&')
    return true;
}
return false;

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That's assuming you know the length of your array, which you should.
Alternatively, assuming it has a sentinel value e.g. \0, you can just loop while(arr[n] != '\0')

Code:

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for(int n=0;n<length;n++)

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In C code?

Thanks a lot! Didn't know that it could be done that simple.

Code:

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    int d;
    for(d=0;d<strlen(cur);d++) {
        if(cur[d] == '&')
            printf("you wrote & sign\n");
        }

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Quote:

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Originally Posted by SKeane

Code:

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for(int n=0;n<length;n++)

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In C code?

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Well, close enough. I appear to have thought I was in the C++ forum.

Quote:

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Originally Posted by tidemann

for(d=0;d<strlen(cur);d++)

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Instead of strlen in loop, calculate the length of cur in front of the loop.

If cur is NULL terminated...

Code:

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if ( strchr(cur, '&') != NULL )
{
    printf("You wrote a & sign\n");
}

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