KnR, Ch1, ex 1-10

Hello, I'm reviewing KnR after not having done much programming in about 7 years. I just encountered some behavior I can't quite figure out in the program I made for ex. 1-10 ("Write a program to copy its input to its output, replacing each tab by \t , each backspace by \b , and each backslash by \\ . This makes tabs and backspaces visible in an unambiguous way".)

Can anybody tell me why, when typing "\" & hitting return the output of the code below should be this? (the tab handling statements seem to be just fine)

--------------------------

\
hello feck

----------------------------

Code:

---



while(  (c=getchar())  !=EOF  ){
   
    if (c=='\t'){
      printf("\\");
      printf("t");
    }
   
    if (c!='\t'){
      if(c=='\\') printf("hello ");{
                if(c!='\\') printf("feck ");
      }
    }
  }//while
  return 0;

---

thank you in advance

Despite your indentation, your code reads as

Code:

---

    if (c!='\t'){
      if(c=='\\') printf("hello ");
      {
        if(c!='\\') printf("feck ");
      }
    }

---

With a \, you get hello printed, with the if(c=='\\'), because \ is not equal to a tab
With a newline, you get feck printed, because newline isn't a tab, and it isn't \\ either



Why is if(c=='\\') inside another if statement?

Shouldn't it be
if ( c == '\t' )
if ( c == '\\' )
if ( c == '\b' )