I need help with a password program

I am trying to make a password word program
that uses the number of characters in the password
so i need help counting the characters?????

Please be specific if you want useful answers.

store the password in a string and get the number of characters with the size() member function.

Code:

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#include <iostream>
#include <string>

int main() {
    std::string pass;

    pass = "mypassword";

    std::cout << "Password has " << pass.size() << " characters";

}

---

Code:

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#include <string>
#include <iostream>

using namespace std;

int main( void )
{
        string        Password = "is Secret",
                Attempt  = "";

        cout<< "Enter Password - ";
        getline( cin, Attempt );
// or getline( cin, Attempt, '\n' ); but
// it automatically terminates at '\n', I think

        if ( Password == Attempt ) cout<< endl << "Successful login!";
        else cout<< endl << "No good!";

        return 0;
}

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Password.size() returns the size

Quote:

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Originally Posted by twomers

Code:

---

#include <string>
#include <iostream>

using namespace std;

int main( void )
{
        string        Password = "is Secret",
                Attempt  = "";

        cout<< "Enter Password - ";
        getline( cin, Attempt );
// or getline( cin, Attempt, '\n' ); but
// it automatically terminates at '\n', I think

        if ( Password == Attempt ) cout<< endl << "Successful login!";
        else cout<< endl << "No good!";

        return 0;
}

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Password.size() returns the size

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I hope i dont sound stupid but when i attempted to use this code, after you input a password it seems it closes so i added a simple cin.ignore(); before the return, anyways here is a code that worked for me.

EDIT: Maby it's because im using Dev-C++ ???

Code:

---

#include <string>
#include <iostream>

using namespace std;

int main( void )
{
    string Password = "thepass",
          Attempt = "";
         
    cout<< "Enter Password: ";
    getline( cin, Attempt );
   
    if ( Password == Attempt ) cout<< endl << "Succsessful Login!";
    else cout<< endl << "No Good!";
    cin.ignore();
    return 0;
}

---

You may run into funny things like these that will seem kind of unintuitive. There's a nice FAQ that addresses some of Dev C++'s quirks that you might like.

http://www14.brinkster.com/aditsu/dev-cpp-faq.html

Quote:

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When I run my console application, the black window flashes a bit then closes automatically. How can I see the output of my program?

Your program does exactly what you tell it to do, and you didn't ask it to wait before closing. You can add a command to wait for keyboard input before the program exits (e.g. before the return from main). A very simple example is system("pause"); which executes the "pause" system command (portability note: this only works in Windows and DOS); you need to #include <cstdlib> (or #include <stdlib.h> for C programs) if the compiler complains about the system function. Or you can use an instruction that reads something from the keyboard (e.g. cin.get();, getchar(); or cin>>variable;). In that case you may need to clear the input buffer before reading, e.g. cin.sync(); before cin.get();. Another option is to run your program from the command prompt; this is especially useful if you don't want it to wait before closing, or if it crashes before it reaches the keyboard-reading instruction.

---

Code:

---

#include <iostream>
#include <string>
using namespace std;

int main()
{
    string atmpt; // Attempt
    string pass = "password"; // Password
 
    cout << "Enter your password: ";
   
    cin >> atmpt;
   
    if ( atmpt.length() > 10 )
    {
        cout << "You entered nore than 10 charecters";
    }
    else
    {
        cout << "You're logged in!";
    }
   
    return 0;
}

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You can set width to your input!!

Code:

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cin >> setw(8) >> attempt;

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And the header file for that is "iomanip"

Quote:

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Originally Posted by stuart_cpp

Code:

---

#include <iostream>
#include <string>
using namespace std;

int main()
{
    string atmpt; // Attempt
    string pass = "password"; // Password
 
    cout << "Enter your password: ";
   
    cin >> atmpt;
   
    if ( atmpt.length() > 10 )
    {
        cout << "You entered nore than 10 charecters";
    }
    else
    {
        cout << "You're logged in!";
    }
   
    return 0;
}

---

---

I would avoid telling potential hackers that your password is of any certain length.

Quote:

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Originally Posted by MacNilly

I would avoid telling potential hackers that your password is of any certain length.

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A brute-force hackers dream, I'd say.

Code:

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if(passEntered != passStored)
  std::cout << "You didn't enter the correct password, which should be \"" << passStored << "\".\n";

---

Quote:

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Originally Posted by SlyMaelstrom

A brute-force hackers dream, I'd say.

Code:

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if(passEntered != passStored)
  std::cout << "You didn't enter the correct password, which should be \"" << passStored << "\".\n";

---

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I'm not sure if you're agreeing w/ me or not.

But yeah, telling the length of the password is a BAD idea.

Um, reeL, there is actually an amazingly simple way to view the output. Run the program from the command line, as it was meant to be run. You kids have it so easy nowadays, what with IDEs and such...

you can use strcmp()

Code:

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// assume string is a variable where you place your string
if(!strcmp(string,"mypassword)) cout<< "wrong password"

---

yup giving a length of password can be BAD idea (^^)

Quote:

---

When I run my console application, the black window flashes a bit then closes automatically. How can I see the output of my program?

Your program does exactly what you tell it to do, and you didn't ask it to wait before closing. You can add a command to wait for keyboard input before the program exits (e.g. before the return from main). A very simple example is system("pause"); which executes the "pause" system command (portability note: this only works in Windows and DOS); you need to #include <cstdlib> (or #include <stdlib.h> for C programs) if the compiler complains about the system function. Or you can use an instruction that reads something from the keyboard (e.g. cin.get();, getchar(); or cin>>variable. In that case you may need to clear the input buffer before reading, e.g. cin.sync(); before cin.get();. Another option is to run your program from the command prompt; this is especially useful if you don't want it to wait before closing, or if it crashes before it reaches the keyboard-reading instruction.

---

What happened to
system("PAUSE")
??

My window closes immediately as well, so I do that.

Or I use a never-ending for-loop, and then break it if the requirements are met.

Quote:

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Originally Posted by mburt

What happened to
system("PAUSE")
??

---

What happened to the FAQ?
FAQ > How do I... (Level 1) > Stop my Windows Console from disappearing everytime I run my program?

This code may help u :) although it is very very very simpl. Just add the code that returns the characters :)

Code:

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//Logical operators
#include <iostream>
#include <string>
#include <conio.h>

using namespace std;

int main()
{
    cout << "\tGame Designer's Network\n";
    int security = 0;
   
    string username;
   
    cout << "\nUser Name: ";
    cin >> username;
   
    string password;
    cout << "\nPassword: ";
    cin >> password;
   
    if (username == "S.Meier" && password == "civilization")
    {
                cout << "\nHey, Sid.";
                security = 5;
    }

    if (username == "Josh" && password == "Josh")
    {
                cout << "\nWhat's up, Josh.";
                security = 5;
    }
       
        if (!security)
        cout << "\nYour LogIn has failed";
       

getch();
return 0;
}

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