Newbie Question integers and variables

Hi all!

I'm a newbie and wonder why:

int a, b, c;
a = 5;
b = 12000;
c = a*b;
printf("%d", c);

does not yield 60000

Please help!

Um, it looks okay to me.

60000 is probably to big for an integer to hold on your system. Use a long int instead, and write

Code:

---

printf("%ld", c);

---

to specify a long digit.

Ah, that makes sense. I thought an integer could hold higher numbers... guess it does depend on the system and/or the compiler...

Thanks! :D

BTW what complier/os are you using?

The thing is, I'm not, but I have this "study" question that asked this question and I couldn't figure out why.... it wasn't suppose to work...

Very sneaky way to get people to do your work GJ ;)

yeah.... now I have a different problem I have no answer to...... maybe you could answer exactly what this function does with the string...

Code:

---

void foo(char *string, int length)
{
  char temp;

  if(length < 2)
    return;
  else {
    temp = *string;
    *string = string[length - 1];
    string[length -1] = temp;
    foo(string+1, length-2);
  }
}

---

it recursively reverses the characters in the string. If this is homework, read the board policy.

Quote:

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Originally Posted by MrMe

yeah.... now I have a different problem I have no answer to...... maybe you could answer exactly what this function does with the string...

---

I've got a better idea. Make a test program, stick the function in it, and find out for yourself.


Quzah.