Undeclared Identifier

This date program is supposed to take in the written date

Code:

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Date g( January, 12, 1994 ); // written date

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and convert it, displaying it as 01/12/94 and 12/1994 (ordinal, or as some call it, Julian). I'm getting the error "January, undeclared identifier". I'm not sure what is wrong? Thanks in advance for any info.

Code:

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#include <iostream>
#include <iomanip> // for setfill and setw
#include <cstring> // for strings

using namespace std;

class Date // typically stored in header file date1.h
{
  public:
      Date( const char* , int , int ); // constructor for January 15, YYYY
      void printJulian() const;  // print date in DDD YYYY format
      void printMDY() const;  // print date in MM/DD/YY
      void printLong() const;  // print date something like June 14, 2006
      ~Date();  // provided to confirm destruction order
           
  private:
      int month;
      int day;
      int year;
      int julian;
      int checkDay( int ) const; // function tests proper day
      int getMonthNumber( const char* ) const; // to compare January to 1


}; // end class Date; end of date1.h header file

  const char* monthTable[13] = {"invalid","January","February","March","April","May","June","July","August","September","October","November","December"

}; // global array


Date::Date(const char* _month, int _day, int _year) // untested
{
  year = _year;                // should validate yr
  month = getMonthNumber(_month);
  day = checkDay( _day );      // validate the day
}

void Date::printJulian() const // prints as DDD YYYY (ordinal/gregorian)
{
  int calculator = 0;

  if (month == 1)
      calculator = 0;
  else if (month == 2)
      calculator = 31;
  else if (month == 3)
      calculator = 59;
  else if (month == 4)
      calculator = 90;
  else if (month == 5)
      calculator = 120;
  else if (month == 6)
      calculator = 151;
  else if (month == 7)
      calculator = 181;
  else if (month == 8)
      calculator = 212;
  else if (month == 9)
      calculator = 243;
  else if (month == 10)
      calculator = 273;
  else if (month == 11)
      calculator = 304;
  else if (month == 12)
      calculator = 334;

  int gregorian;
  gregorian = (day + calculator);
  cout << setfill('0') << setw(3) << gregorian << "/" << year;


} // end function printJulian

void Date::printMDY() const // prints as MM/DD/YY
{
  cout << setfill('0') << setw(2) << month << '/' << setw(2) << day << '/' << setw(2) << year;

} // end function print3

void Date::printLong() const // prints, for example, March 12, 1988 - written format
{
        const char* monthArray[13] = {"null","January","February","March","April","May","June","July",
                "August","September","October","November","December"};

    cout << monthArray[month] << " " << day << ", " << year;

} // end function print4

// output Date object to show when its destructor is called
Date::~Date()
{

} // end ~Date destructor

// utility function to confirm proper day value based on
// month and year; handles leap years, too
int Date::checkDay( int testDay ) const
{
  static const int daysPerMonth[ 13 ] =
      { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };

  // determine whether testDay is valid for specified month
  if ( testDay > 0 && testDay <= daysPerMonth[ month ] )
      return testDay;

  // February 29 check for leap year
  if ( month == 2 && testDay == 29 &&
      ( year % 400 == 0 ||                     
        ( year % 4 == 0 && year % 100 != 0 ) ) )
      return testDay;

  cout << "Day " << testDay << " invalid. Set to day 1.\n";

  return 1;  // leave object in consistent state if bad value

} // end function checkDay; end of date1.cpp

int Date::getMonthNumber(const char* _month) const
{
  int key = 0;
      for (int i = 1; i< 13;i++){
        if (!strcmp(_month,monthTable[i]))
        {
            key = i;
            break;
        }
      }
  return key;
}


int main()
{

  Date g( January, 12, 1994 ); // fourth date, written

  cout << "\nFourth date entered is: ";
  g.printLong();
    cout << "\nFourth date in DDD/YYYY (Gregorian) format: ";
  g.printJulian();
  cout << "\nFourth date in MM/DD/YY format: ";
  g.printMDY();
  cout << "\nFourth date in written format: ";
  g.printLong();
  cout << endl;

  return 0;

} // end main

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Quote:

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Code:

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Date g( January, 12, 1994 );

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The function takes written date being the first argument a c-string as you can see in it's declaration:

Code:

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Date( const char* , int , int );

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So try calling it as:

Code:

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Date g("January",12,1994);

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As without the "" the compiler assumes January is the name of a variable. This ought to do the trick...

cheers

Thank you so much, yes it works! Glad to see it was simple. :)