Digits reverse

i have write a program digits reverse.......but prob here....how to gets output with negatif number....

e.g
input : -123456
output : -654321

this my program

Code:

---

#include <iostream>
#include <stdlib.h>

using namespace std;

int main()
{
int a,b,c,d,e,f,sum,find=0;

cout << "Enter an integer digits: ";
cin >> sum;


a = (sum % 10);

b = (sum % 100);
b = b / 10;

c = (sum % 1000);
c = c / 100;

d = (sum % 10000);
d = d / 1000;

e = (sum % 100000);
e = e / 10000;

f = (sum % 1000000);
f = f / 100000;


        if (sum<10)
          { 
            cout << "The Reverse Order is  : " << endl;
            cout << a << endl;
          }
        else if (sum<100)
        {
            cout << "The Reverse Order is  : ";
            cout << a << b << endl;
          }
        else if (sum<1000)
          {
            cout << "The Reverse Order is  : ";
            cout << a << b << c << endl;
          }
        else if (sum<10000) 
          {
            cout << "The Reverse Order is  : ";
            cout << a << b << c << d << endl; 
          }
        else if (sum<100000)
          {       
            cout << "The Reverse Order is  : ";
            cout << a << b << c << d << e <<  endl; 
          }
          else if (sum<1000000) 
          {       
            cout << "The Reverse Order is  : ";
            cout << a << b << c << d << e << f << endl; 
          }
         
          else if ((sum<0) && (sum<10))
          {
            cout << "The Reverse Order is  : ";
            cout <<"-"<< a << endl;
          }
 
     
       
  cout << "\n\n\n\n";     

 system("PAUSE");
 return 0;
 
 }

---

Code:

---

/* ...Before the parsing... */

if (sum < 0) {
  sum *= -1;
  isNegetive = true;

/* ... After the parsing ... */

if (isNegetive)
  sum *= -1;
  // Or if you wish...
  // cout << a * -1 << b ...

---

Quote:

---

i have write a program digits reverse

---

You can do the whole program in only a few lines that will handle any size number if you turn the number into a string type and then reverse the string.

Quote:

---

Originally Posted by SlyMaelstrom

Code:

---

/* ...Before the parsing... */

if (sum < 0) {
  sum *= -1;
  isNegetive = true;

/* ... After the parsing ... */

if (isNegetive)
  sum *= -1;
  // Or if you wish...
  // cout << a * -1 << b ...

---

---

input :-123456
output:-6-5-4-3-2-1

7stud....
im a beginner....so i write the program how i understand...
u have any tips??...i appreciate it...thanks

Quote:

---

Originally Posted by mufanz

input :-123456
output:-6-5-4-3-2-1

---

Congratulations, all that means is you implemented it wrong. You're only supposed to multiply the leading digit a by -1.

thanks....program success

Code:

---

#include <iostream>
#include <string>
#include <sstream> //ostringstream
using namespace std;

int main()
{
        int num = 1234;

        ostringstream myOutputString; //creates a special kind of variable(see below)

        myOutputString<<num;
        //myOutputString works just like 'cout'
        //except you're outputting 'num' into a variable
        //instead of to the console window.
        //You can output any type into the variable.


        string myString = myOutputString.str();
        //the str() function returns a string that contains
        //whatever is inside myOuputString
       
        cout<<"This is now a string: "<<myString<<endl;

        //strings have many functions for manipulating them,
        //but you can just use a string's length() function and a for
        //loop to reverse a string.  A string can be treated just like
        //and array of characters.

        string reversed;

        for(int position = myString.length() - 1; position >= 0; position--)
        {
                reversed = reversed + myString[position];
        }

        cout<<reversed<<endl;

         
    return 0;
}

---