Why does the code excute, but I get no print message?

Could someone give me some kind of technical explanation why the follow code will execute, but won't print anything out?

Code:

---

#include <stdio.h>
#include <signal.h>
#include <unistd.h>

static void sig_alarm(int signo) {
  if(signo == SIGALRM)
    printf("Signal Caught \n");
}

unsigned int sleep1(unsigned int nsec){
  if(signal(SIGALRM,sig_alarm) == SIG_ERR){
    return(nsec);
  }
  alarm(nsec);
  pause();
  return(alarm(0));
}

int main(void) {
  sleep(5);
  return 0;
}

---

Thanks

Because you call the wrong sleep function

Code:

---

int main(void) {
  sleep1(5);  // not sleep(5)
  return 0;
}

---

Kurt

you are not calling the fucntion properly. check out the code again. the main cals sleep fucntion. which seems to call sleep1 in your code.

ssharish2005

Yeah, sleep() is actually a function which causes the program to...for lack of a better word sleep, for 5 miliseconds or something or another....which is why the program compiled with no problems. Change the sleep() call in the main to sleep1() and you should be fine.