String copying

Right, this is a kinda continuation of the last post, but in a simpler method!

Basically, i want to (in psuedo-code):

Code:

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string1 = ".example";
string2 = "";

/* copy string1 to string2 ignoring the first char */
string2 = "example";

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Does anybody know how i can do this???

In the header "string.h" exists a function called strncpy. :)

Code:

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strncpy(string2, string1, strlen(string1));

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>Does anybody know how i can do this???

Code:

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strcpy( string2, string1+1 );

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first of all, the destination cannot be a string literal like you posted. Any attempt to change string literals will probably crash your program. You need to create a character array

Code:

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char string2[10];
char * string1 = ".example";
strcpy(string2, string1+1);

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If you want to add more text to the end of string2 then you have to increase its size from 10 to however big you think it might need. Exact size is not important as long as the character array is at least as large as the number of characters you intend to copy there, plus 1 for the null terminator. Don't get too parinoid about wasting a few bytes of space.

Code:

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char string1[] = ".example";
char string2[32];

strcpy(string2, &string1[1]);

printf("%s\n", string2);

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output:

Code:

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example

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apsync, your code is basically identical to ancient dragon's code. &string1[1] is just an ugly way of saying string1+1.

You want to see ugly? I bet I could do it with memcpy. </joke=private>


Quzah.

Quote:

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Originally Posted by quzah

You want to see ugly? I bet I could do it with memcpy. </joke=private>


Quzah.

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you could also do it with a loop :rolleyes:

Thanks people!!! ...I know that the code i posted was not valid, but i just wanted to show what i was stuck with! Now i have the answer, i can complete my sortCompare function so that it sorts the array even if elements of the array have a leading . (i.e. it ignores any leading . when it compares the array elements!)

so the string+1 bit works perfectly!!!! thanks!!!!!

Quote:

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Originally Posted by Ancient Dragon

you could also do it with a loop :rolleyes:

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With memcpy in a loop...


Quzah.

Yes, memcpy is best used in a loop with the third parameter set to 1, for maximum control :p

And just to be sure replace memcpy() with memmove() :P

I guess I should have said (what I really meant) memset... Now that would be fun. ;)


Quzah.