Converting Char Array Loop values to integer

How can I convert the Char array loop values to integers and assign to the interger array?

Code:

---

// write to the procInput array
                        if( atoi(processes[loop]) >= 1 && atoi(processes[loop]) <=9 )
                        {
                                procInput[x] = processes[loop];
                                x++;
                        }

---

procInput is an integer arry and the processes is the char array

Thanks,
AzamSharp

I'm not going to teach you how to think. You'll have to figure out how to do that on your own. You already have the answer right in front of you. Look very closely at your if check. Then go look that up, and see if you can't figure out how to do something with it.


Quzah.

Thanks I will check it out.

Heh, bit of a logical error there.

A good way to do error checking in your program is to output text at various points. Put it into if statements and loops, to see what outputs and how many times.

As quzah said, look at your if statement conditions.

Hi,

Well in the documentation it says that atoi takes in character constant. Dont know what is that suppoed to mean I will do some test today and see what happens.

what is processes[loop]? is it a char or a char*? If it's a char that is a number, just subtract '0' from it, if it's a char* then give it to atoi()

Hi,

well processes is a character array. like this

Code:

---


char processes[10];

for(loop = 0; loop<=10; loop++)
        {
                if(processes[loop] != ',' && processes[loop] != ';')
                {
                        y = processes[loop];
                        printf("The value of y is %d",y);





                       
                        //procList[x] = processes[loop];
                        //x++;
                }
        }

---

so if process = "0,1,2,3", then to get the int value of 1 from item 2 in the array, you would say:

Code:

---

int n = process[2] - '0';

---

Thanks that did the trick :)