Converting Text to Binary (And Back)

I have been searchign and searching and I did find code on this site on how to convert text to binary but that code didn't seem to work... at all. It also didn't seem like it could convert back.

I just need a website or somthing that teaches how to do this, I can only find converters that do this for you.

Any help please?

http://cboard.cprogramming.com/showthread.php?t=68863

here a post that was done a couple days ago,
you can look at my post, the show easy way using bitset,
to show the binary value.

bitset also let you take a string of 0's and 1's to create
a num/letter/string . the bitset i used was <32> becuase
he was using numbers, but you can change it to 8 or any other
number of places.

Alright well now I think I am getting somewere but here is the code I made from yours...

Code:

---

#include <iostream>
#include <bitset>
#include <string>

using namespace std;

int main()
{
    bitset<32> b(3);
        cout << b << endl;
        cin.get();
        return 0;
}

---

it is watered down just so I can easily test it. But this is the line of code I am confused about:

bitset<8> b(3);

How do I use that? if I put b("a") it just gives an error.

> bitset<32> b("a");
bitset<32> b('a');
:confused:

Ahh ok that worked!

I'm guessing it can't do a whole string and that is why you do it character by character?

Ahh ok that worked!

I'm guessing it can't do a whole string and that is why you do it character by character?

Anyways thanks alot!

>I'm guessing it can't do a whole string and that is why you do it character by character?

I don't think you can do a whole string. You'd have to use a vector of bitset, then use a loop to print each element (or use the copy algorithm to copy to cout).

Code:

---

  vector < bitset<8> > b;
   
  b.push_back('D');
  b.push_back('O');
  b.push_back('G');
       
  for (int i=0; i<b.size(); i++)
      cout << b[i] << endl;

---

hmmm alright and one more question. How would I convert binary back to text?

Code:

---

#include <bitset>
#include <iostream>
#include <string>

using namespace std;

int main()
{
  bitset<32> b ( string ( "11111111" ) );

  cout<< b <<'\n'
    << static_cast<char> ( b.to_ulong() ) <<'\n'
    << static_cast<int> ( b.to_ulong() ) <<'\n';
  cin.get();
  return 0;
}

---

alright I got one last problem. How do I turn b (the binary number) into a LPSTR or string. I can't type cast it so I'm kinda lost on that. And turning into a number won't work for my purposes.

if you have a bunch of letter that you turned to binary, just
go thru with a loop and add teh to a string then you can
have a string?

But I can't get a string from the b.

i dont understand exactly what your wanting, explain a little better?

I'm not sure if this helps or not, but you can go from string to b, so I'm not sure you would need to go the other way, since you already have a string.

Code:

---

#include <iostream>
#include <string>
#include <vector>
#include <bitset>

using namespace std;

int main()
{
  string food("PIZZA");
  vector < bitset<8> > b;

  for (int i=0; i<food.length(); i++)
      b.push_back(food[i]);
       
  for (int i=0; i<b.size(); i++)
      cout << b[i] << endl;

}

---

It's possible to go from b to string, but not trivial. At least I can't think of a quick way. But if you need to, it can be done.

I want to do this (This is for a dll)

return (LPSTR) b;

Sence that doesn't work I need anouther way if bossible.


EDIT: Ok I will explain this again but better.

b contains the binary 01100110. I need to make b a string containing that binary so I can return it as a string.

You can use the bitset member to_ulong to make the conversion.

Code:

---

#include <iostream>
#include <string>
#include <vector>
#include <bitset>

using namespace std;

int main()
{
  string pizza("CHEESE");
  vector < bitset<8> > b;

  for (int i=0; i<pizza.length(); i++)
      b.push_back(pizza[i]);
       
  for (int i=0; i<b.size(); i++)
      cout << b[i] << endl;

  string pizza_name;
  for (int i=0; i<b.size(); i++)
  {
      char c = b[i].to_ulong();
      //cout << (int) c << endl;
      pizza_name = pizza_name + c;
  }
  cout << pizza_name << endl;

}

---

My knowledge of C++ only goes back a single day (that's how long I've been doing C++, ouch), so don't blame me if I'm wrong, but can you typecast or use a pointer?

Well I said I can not type cast in about 3 or so other posts, gives me an error. And now that I have a string...... Game Maker gives me a stupid error. One problem after the other.

Also if I just return it as (float) b.to_ulong it gives me the acsii code for the letter. Why is it giving me the ascii code and not binary?

And I think an LPSTR is basically a char array, once you have a string, then you can store that into a char array:

Code:

---

char carray[100];
strcpy( carray, pizza_name.c_str() );

---

Or if your LPSTR already has memory allocated for it, then use strcpy() to copy to the LPSTR.

EDIT: added c_str()

>(float) b.to_ulong
You don't want float, you want char:
(char) b.to_ulong()
That will give you one char, which you could store straight to a char array, if you wish.

Allright I think all problems on the C++ side are fixed so the rest is up to me now.

Thanks alot!

Code:

---

#include <bitset>
#include <iostream>
#include <string>
#include <sstream>

using namespace std;


int main()
{
        string binary;
        stringstream ss;
        bitset<8> b('a');
        ss << b;
        binary = ss.str();
        cout << binary << endl;
        cin.get();
        return 0;
}

---

is this the kind of string you wanted, the string of 1's and 0's?