generate a random number

hi all,

i need to know how to generate a number..influenced by percentages..

how do u write code ...so for example, there is a 95% chance that a variable = 1 and the other 5% of the time it equals 0...

right now i got

#include <cstdio>
int random = rand () % 2;

but this is randomly giving me 1 or 0...

thanks.

Well for a percentage, you need rand() % 100

So to get to where you want to be
int random = rand() % 100 > 95 ? 1 : 0;

Why do more people use rand than

Code:

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random(int);

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.

Because rand() is a standard function, and random() isn't

Hi, just a follow up question to this thread. So how would you write the code if you have 3 numbers, for example, 60% probability of generating 0, 35% generating 1 and 5% generating 2. Thanks a lot:)

Code:

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int random = rand()%100;
int result;

if(random < 60)

    result = 0;

else if(random >= 60 && < 95)

    result = 1;

else

    result = 2;

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