Super Function like in JAVA

I have question about constructors,

If i have

Code:

---

Class A {
  private:
    int x;
    int y;
}

Class B : public A {
  private:
    int x;
    int y;
    int z;
}

---

Is there a way when I code the constructors I can leave the parent constructor and just do this->y = y; and since Class B calls the parent class, x,y would just be reduntent. This is similar to the command SUPER in JAVA. Just wondering. Thanks.

Not quite sure what you mean. Are x from A and x from B supposed to be the same thing? (Because they aren't.)

The equivalent of this Java snippet:

Code:

---

class Base
{
  public Base(int arg1) {
  }
}

class Derived extends Base
{
  public Derived(int arg1, int arg2) {
    super(arg1);
  }
}

---

... is this C++ code:

Code:

---

class Base
{
public:
  Base(int arg1) {
  }
}

class Derived : public Base
{
public:
  Derived(int arg1, int arg2)
    : Base(arg1)
  {
  }
}

---

If you want to have easier refactoring (changing the base class) you can add a typedef for the base class at the start and call it super:

Code:

---

class Base
{
public:
  Base(int arg1) {
  }
}

class Derived : public Base
{
  typedef Base super;
public:
  Derived(int arg1, int arg2)
    : super(arg1)
  {
  }
}

---

In general, what you've shown there should be avoided at all costs (in any language). Your shadowing variables... tsk, tsk ;)

Another thing, B can not get to A's variables without going through A's interface since the variables are private.

Yes... Good old C++. Only your friends can see your privates... not your children.


Yeah... couldn't help myself. Sorry.