Print computer/system name

I need my program to print out the name of the computer. Is this possible through C++ at all?

Thanks in advance.

Code:

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#include<windows.h>
char buffer[256];
DWORD len = 256;
GetComputerName(buffer, &len);
cout<<buffer<<endl;

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Quote:

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Originally Posted by jinhao

Code:

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#include<windows.h>
char buffer[256];
DWORD len = 256;
GetComputerName(buffer, &len);
cout<<buffer<<endl;

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Thank you VERY much. Worked perfectly.

Next time, say which OS/Compiler you're using.
It was just a lucky guess that you were using windows.

Quote:

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Originally Posted by Salem

Next time, say which OS/Compiler you're using.
It was just a lucky guess that you were using windows.

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Ah. Thanks. I'll be sure to state that next time. :o.

heihei, i am so lucky :)

Thanks for the previous help, guys. However, I must compile it this code on a Unix machine now. I'm using the standard Unix build, cc xxx.cpp.

How should I print out the system name using that? I assume that I should include a different header file than windows.h.

Thanks in advance.

Hum.. I dunno .. but you could try to acess the environement variables and try to see if there's something that mathces the computer name

Code:

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#include <iostream>

int main(int argc, char *argv[], char *env[]){
    int i;
    for(i=0;env[i];i++){
        std::cout<<env[i]<<std::endl;
    }
    return 0;
}

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NOTE: this main declaration ISN'T standard, although it's provided with many compilers as extension., I think. Please correct me if wrong.

http://www.opengroup.org/onlinepubs/...bd/envvar.html
http://www.cplusplus.com/ref/cstdlib/getenv.html

Quote:

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Originally Posted by xErath

Hum.. I dunno .. but you could try to acess the environement variables and try to see if there's something that mathces the computer name

Code:

---

#include <iostream>

int main(int argc, char *argv[], char *env[]){
    int i;
    for(i=0;env[i];i++){
        std::cout<<env[i]<<std::endl;
    }
    return 0;
}

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NOTE: this main declaration ISN'T standard, although it's provided with many compilers as extension., I think. Please correct me if wrong.

http://www.opengroup.org/onlinepubs/...bd/envvar.html
http://www.cplusplus.com/ref/cstdlib/getenv.html

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That looks good. Although I'm not sure whether it'll be fine for Unix. I will try it once I get to the office Friday.

Any other ideas, guys? :).

Quote:

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Originally Posted by xErath

Hum.. I dunno .. but you could try to acess the environement variables and try to see if there's something that mathces the computer name

Code:

---

#include <iostream>

int main(int argc, char *argv[], char *env[]){
    int i;
    for(i=0;env[i];i++){
        std::cout<<env[i]<<std::endl;
    }
    return 0;
}

---

NOTE: this main declaration ISN'T standard, although it's provided with many compilers as extension., I think. Please correct me if wrong.

http://www.opengroup.org/onlinepubs/...bd/envvar.html
http://www.cplusplus.com/ref/cstdlib/getenv.html

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Yeah, that doesn't seem to be working on Unix machines :(. Any other ideas, guys? :o.

Code:

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NAME
      uname − get name and information about current kernel

SYNOPSIS
      #include <sys/utsname.h>

      int uname(struct utsname *buf);

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Quote:

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Originally Posted by Salem

Code:

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NAME
      uname − get name and information about current kernel

SYNOPSIS
      #include <sys/utsname.h>

      int uname(struct utsname *buf);

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I get this error :o - fatal error C1083: Cannot open include file: 'sys/utsname.h': No such file or directory
Error executing cl.exe.

Oh please - you asked for a unix answer and I gave you one.
Then you turn around and try and compile it with a windows compiler! :rolleyes:

Quote:

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Originally Posted by Salem

Oh please - you asked for a unix answer and I gave you one.
Then you turn around and try and compile it with a windows compiler! :rolleyes:

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It has to work on both :o.

Tough - it won't, nor can it ever work on both.

Certainly, there's no standard way to find out.

I suppose you could find some very common library somewhere, which might happen to tell you which machine you're on...

Quote:

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Originally Posted by Salem

Tough - it won't, nor can it ever work on both.

Certainly, there's no standard way to find out.

I suppose you could find some very common library somewhere, which might happen to tell you which machine you're on...

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I'll look into it. Thanks for your help though :o.

Quote:

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Originally Posted by JizJizJiz

It has to work on both :o.

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Why should it ?!? It's OS specific coding, therefore you won't find support for other OS rrather that Windows on a MS compiler...

Code:

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#define WINSOURCE (defined(WIN32) || defined(WIN64))

#if WINSOURCE
#include<windows.h>
#else
#include<sys/utsname.h>
#endif

char *get_pcname(){
    static char buffer[256];
#if WINSOURCE
    DWORD len = 256;
    GetComputerName(buffer, &len);
#else
    struct utsname booh;
    memset(&booh,0,sizeof(booh));
    uname(&booh);
    int len = strlen(booh.nodename);
    memcpy(buffer,booh.nodename,len>255?255,len);
    buffer[255]=0;
#endif
    return buffer;
}

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Quote:

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Originally Posted by xErath

Why should it ?!? It's OS specific coding, therefore you won't find support for other OS rrather that Windows on a MS compiler...

Code:

---

#define WINSOURCE (defined(WIN32) || defined(WIN64))

#if WINSOURCE
#include<windows.h>
#else
#include<sys/utsname.h>
#endif

char *get_pcname(){
    static char buffer[256];
#if WINSOURCE
    DWORD len = 256;
    GetComputerName(buffer, &len);
#else
    struct utsname booh;
    memset(&booh,0,sizeof(booh));
    uname(&booh);
    int len = strlen(booh.nodename);
    memcpy(buffer,booh.nodename,len>255?255,len);
    buffer[255]=0;
#endif
    return buffer;
}

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Understood. I was a bit slow on Friday...doing lots of work at once :o. Sorry.