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Hey everyone, I'm having a little bit of trouble writing a program that counts 2 vowels side by side as one vowel. For example in the word feet, there are 2 vowels e, rather than count them as 2 seperate vowels, I have to come up with code that counts any 2 vowels side by side as one vowel. If anyone can give me some advice I would greatly appreciate it.
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It appears that you are posting a homework assignment or other project.
Please don't ask people to do all your work for you, See the announcement on Homework at the top of all forums to see what is acceptable or PM me. Basically people are happy to help, but they're not going to do it all for you.
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Feel free to PM me with any questions.
Good Luck,
Kermi3
this might help you
s.s.harishCode:for(i=0;str[i]!='\0';i++)
{
switch(str[i])
{
case 'a': if(str[i+1]=='a') printf("A is a vowel which is side by side\n"); break;
case 'e': if(str[i+1]=='e') printf("E is a vowel which is side by side\n"); break;
case 'i': if(str[i+1]=='i') printf("I is a vowel which is side by side\n"); break;
case 'o': if(str[i+1]=='o') printf("O is a vowel which is side by side\n"); break;
case 'u': if(str[i+1]=='u') printf("U is a vowel which is side by side\n"); break;
}
}