Program to reverse a number. small error with it..

hi! heres my program:

#include <stdio.h>
#include <math.h>
#define NEWLINE '\n'

int main(void){
int num;
int reverse(int n);

printf("Enter a positve integer: \n");
scanf("%i \n", &num);

printf("The reverse number is: %i \n", reverse(num));

return 0;
}

int reverse(int n)
{
int rev_num = 0, k = 0,i =2, mult = 1;
int rev_digit, digitcount;
int digits(int r);

digitcount = digits(n);

while((k <= digitcount) && (digitcount != 0))
{
rev_digit = n % 10;

k++;
mult = pow(10, (digitcount - k));

rev_num = rev_num + (rev_digit * mult);
n = n / 10;
}
return rev_num;
}

int digits(int r){
int count = 0;

while(r != 0)
{
r = r/10;
count++;
}

return count;
}


Output:
Enter a postive number:
8002033 /* for example */
2
/* this is where the problem occurs. after i enter 8002033, the program ask for another number, it doesnt matter what i enter, i just need to enter something */

The reverse is 3302008
/* this part seems correct */

So can anyone help me? i dont know why they need me to enter another number after 8002033!! :confused:

sorry heres the tagged code, i missed the top post

Code:

---

#include <stdio.h>
#include <math.h>
#define NEWLINE '\n'

int main(void){
        int num;
        int reverse(int n);

        printf("Enter a positive integer: \n");
        scanf("%i \n", &num);

        printf("The reverse number is: %i \n", reverse(num));
        return 0;

}

int reverse(int n){
        int rev_num = 0, k = 0,i =2, mult = 1, rev_digit, digitcount;
                int digits(int r);
 
                digitcount = digits(n);

        while((k <= digitcount) && (digitcount != 0))
                {
                    rev_digit = n % 10;
            k++;
            mult = pow(10, (digitcount - k));
            rev_num = rev_num + (rev_digit * mult);
                    n = n / 10;           
        }
                return rev_num;                   
}

int digits(int r){
        int count = 0;

        while(r != 0)
                {
              r  = r/10;
              count++;
                }
        return count;
}

---

Code:

---

scanf("%i \n", &num);

---

Try

Code:

---

scanf("%i", &num);

---

YES!!! it worked!!
thank you!!!
you are brilliant!!!
thank you!!!
thank you!!!
thank you!!!

Assuming that you're using unsigned int number as input and ASCII,

Code:

---

void
print_reverse_number(const unsigned int number)
{
        const unsigned int      quotient = number / 10;
        const unsigned int      remainder = number % 10;


        putchar(remainder + '0');

        if (quotient != 0)
                print_reverse_number(quotient);
}

---

Code:

---

sprintf( buf, "%d", num );
for( x = strlen( buf ) -1; x > -1; x-- )
    putchar( buf[x] );

---

Quzah.

Bah quzah you forgot to check to see if its negative first ;)

There you go thinking negative again...

Quzah.

Always