C++ to C

Want to convert these C++ to C??

(1)

Code:

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#include <iostream.h>
#include <iomanip.h>


// Print out the first n Fibonacci numbers. n is assumed to be >= 1.
void fibo ( int n )
{
    int current = 1;      // The value of the (i)th fibonacci number
    int next    = 1;      // The value of the (i+1)th fibonacci number

    cout << "\n\n\t  I \t Fibonacci(I) \n\t=====================" << endl;
    for ( int i = 1; i <= n; i++ ) {
        cout << "\t" << setw(3) << i <<  "\t\t"
            << setw(4) << current << endl;
        int next2 = current + next;
        current = next;
        next    = next2;
    }
}

int main ( void )
{
    int n;        // The number of fibonacci numbers we will print

    cout << "How many Fibonacci numbers do you want to compute? ";
    cin  >> n;
    if ( n <= 0 )
      cout << "The number should be positive." << endl;
    else
      fibo ( n );

    return 0;
}




#include <iostream.h>

/* Get a positive integer from user */
int getPositive(void){
  int current;

  while( 1 ){
      cout << "Please enter a positive integer: ";
      cin >> current;
      if (current > 0) return current;
      cout << "It should be a positive integer";
  }
}

/* Compute GCD */
int gcd (int dividend, int divisor)
{
  int remaind;

  remaind = dividend % divisor;
  while (remaind != 0) {
      dividend        = divisor;
      divisor        = remaind;
      remaind        = dividend % divisor;
  }
  return divisor;
}

void main(void)
{
  int dividend = getPositive();
  int divisor  = getPositive();

  cout << "The GCD of " << dividend << " and " << divisor << " is "
      <<  gcd(dividend, divisor) << endl;
}

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> Want to convert these C++ to C??
I don't, do you?
How about trying it for yourself.

Basically, replacing cout with printf() will get a lot of it done.

And declaring variables at the beginnig of each function.