end1 error?

Hello! Yes this is for homework, but I only have a few teeny questions. Why, when I compile my program, does it give me three errors about end1 not being in iostream?? I know it is end(one) and not end(lowercase l).

But it still should work, right?

Also, how can I add a check to make sure the input is an integer and not, say, a letter?
Thanks for your help.

Code:

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//Palidrome 2.29

#include <iostream>

int main()
{
        using std::cout;
        using std::cin;
        using std::end1;

        int integer;  //user input
        int digitOne, digitTwo, digitThree, digitFour, digitFive; //breaks up input

        cout << "Enter a five-digit integer: ";  //prompts user
        cin >> integer;  //place-holder for input

        digitOne = integer / 10000;
        digitTwo = integer % 10000 / 1000;
        digitFour = integer % 10000 % 1000 % 100 / 10;
        digitFive = integer % 10000 % 1000 % 10;

        if (digitOne == digitFive && digitTwo == digitFour)
                cout << integer << " is a palindrome." << end1;
        else
                cout << integer << " is not a palindrome." << end1;
       
        return 0;
}

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it is endl not a 1 but a l.

yes I thought it was a 1 too but I found out it was endl.

If that is unclear still (it would be to me) it is a lower case L.



I am sure it is lower case L. I used it before...

Edit: Yes it is lower case L. I just tried it and it worked for me.

Thanks for your reply. The guy who was tutoring me told me that I was wrong when I had endl; in my pseudocode. I guess I should not listen to him next time and find a new tutor.

Do you know of any way I can check for invalid input?

LOL Your welcome. Or listen but maybe not do or check first. LOL


Edit: YES! I helped someone! :) :) :) :)

Do you know how to check for invalid input? I tried to make another while loop but it wouldn't run properly

Code:

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cin >> integer;
if( integer != (/* logical conditions for valid input */) return 0;
digitOne = integer / 10000;

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