Assignment of Two-Dimensional Arrays

Okay, this may seem a bit of an elementary question. If so, please forgive me.

I've initialized a two-dimensional array like so, for example:

Code:

---

static const int 2DARRAY[2][3] = {
  { 1, 2, 3 },
  { 4, 5, 6 }
};

---

I have multiple arrays declared that way and depending on what level we want to load I need to generically access one of the 2D arrays and that's where I keep causing a page fault.

Before realizing my mistake I was trying something similar to this: "const int ***p2dArr = (const int***)2DARRAY;"

When I do a (*p2dArr)[0][0] I crash because the size of the array is unknown. How can I work around this limitation?

you could place the 2D array in a struct/class and then have an container holding instances of the struct/class or you could create a 3D array, static or dynamic, as you need.


int threeDArray[4][2][3];

threeDArray[0] is the first of 4 2D arrays, each 2 by 3, that could be in threeDarray, etc.

The notation for the pointer is exactly the same as if you were passing these arrays to a function

Code:

---

#include <stdio.h>
#include <stdlib.h>

int main ( ) {
    int one[2][3] = { { 1, 2, 3 }, { 4, 5, 6 } };
    int two[2][3] = { { 7, 6, 5 }, { 4, 3, 2 } };
    int (*p)[3];
    int r,c;
    p = one;
    for ( r = 0 ; r < 2 ; r++ ) {
        for ( c = 0 ; c < 3 ; c++ ) {
            printf( "%d ", p[r][c] );
        }
        printf( "\n" );
    }
    return 0;
}

---

Code:

---

static const int T2DARRAY[2][3] = {
  { 1,2,3 },
  { 4,5,6 }
};

const int (*p2dARR)[3]=T2DARRAY;

cout<< p2dARR[0][0];

---

This works on Visual C++ compiler I had to change the name of the array because it starts with a number

It was surprisingly as simple as that... Thanks.