Grateful for help

Hi, I begun the work on this game for some minutes ago:

Code:

---

#include <windows.h>
#include <iostream.h>
#include <stdio.h>
#define WMAX 6
#define PMAX 60
using namespace std;
inline void start(void)
{
    char wayinput[WMAX];
    char pname[PMAX];
    cout << "What do you want to be called?\n";
    cin.getline (pname, 60);
    cout << "\nOk, hello " << pname << ", right now you are in Hilstone Village.";
}
inline void about(void)
{
    cout << "\n                  FT-Adventure is a text-based game";
    cout << "\n                  Made by Marcus Nordh / Sweden in C++.";
}
int main()
{
    HANDLE hOut;
    int selection;
    hOut = GetStdHandle (STD_OUTPUT_HANDLE);
    SetConsoleTextAttribute(hOut,
                        FOREGROUND_RED |
                        FOREGROUND_INTENSITY);


 
    cout << "\n                  **Welcome to a text-based game made in C++!**"<<endl;
    SetConsoleTextAttribute(hOut,
                    FOREGROUND_RED |
                    FOREGROUND_GREEN |
                    FOREGROUND_BLUE |
                    FOREGROUND_INTENSITY);
    cout << "\n                  1. Start\n";
    cout << "\n                  2. Exit\n";
    cout << "\n                  3. About";
    cin>>selection;
    switch(selection)
    {
        case 1:
        start();
        break;
        case 2:
        exit(0);
        break;
        case 3:
        about();
        break;
        default:
        MessageBox(NULL, "Wrong input, quitting", "Error", MB_OK | MB_ICONERROR);
        exit(0);
       
    }
    getchar();
    getchar();
}

---

Somewhere here its wrong:

Code:

---

inline void start(void)
{
    char wayinput[WMAX];
    char pname[PMAX];
    cout << "What do you want to be called?\n";
    cin.getline (pname, 60);
    cout << "\nOk, hello " << pname << ", right now you are in Hilstone Village.";
}

---

cause I can compile it but when I press 1 (start the game) it doesnt let me input my name, instead it says "Ok, hello , right now you..."

Many thanks for answer :p

Make it this::
cin.getline(pname, 60, '\n')
The '\n' tells it to wait until the person hits enter(or should)

you still have a newline in the input stream from when you hit enter after the 1
http://faq.cprogramming.com/cgi-bin/...&id=1043284392

nope Lloy it didn't worked

Noxir i use this function for my clearing input try this

Code:

---

void clearInput()
{
        cin.clear();
        cin.ignore(numeric_limits<int>::max(),'\n');
}

---

heres what yours would look like

Code:

---

#include <windows.h>
#include <iostream>
#include <limits>//added this
using namespace std;

void clearInput()
{
        cin.clear();
        cin.ignore(numeric_limits<int>::max(),'\n');//for this :)
}
inline void start(void)
{
    clearInput();
    char wayinput[WMAX];
    char pname[PMAX];
    cout << "What do you want to be called?\n";
    cin.getline (pname, 60);
    cout << "\nOk, hello " << pname << ", right now you are in Hilstone Village.";
}
//rest of your code

---

thnx a lot :D

I dont understood how does for example (cin.getaline) works, why it work like cin>> ????
Please Im a begginer thx in advance love, abyssphobia

getline gets a string up to a new line character up to a certain length. The standard >> operator just gets up to the first whitespace character.

I believe >> transfers data from the input buffer into the variable until it encounters a char that is inconsistent with the variable. To test it yourself try this:

Code:

---

#include <iostream>
using namespace std;
 
int main()
{
  int num;
  char ch;
  cout << "enter 123#";
 
  //enter 123# yourself
 
  cin >> num >> ch;
  cout << num << endl;
  cout << ch;
}

---

Strings are a little different. Any char is valid for a string. Therefore, the default for >> is to stop at the first whitespace char(space, tab, newline, etc). Therefore, to allow you to put whitespace in a string, you need to use getline(). There are two forms of getline()---one for C style strings and one for STL strings. The C style version has three parameters:

cin.getline(stringToUse, maxNumChar, terminatingChar);

The third parameter defaults to newline, but you can override that by indicating whatever terminating char you wish. The STL string version also has three parameters and use of the terminating char is the same, but the syntax is a bit different:

getline(streamToUse, stringToUse, terminatingChar);

Since an STL string can be of any length desired, there is no need to indicate a maximal length as in the C style string version.

Many asks "why cin.getline instead of cin>>?" the answer is:

• You can't write sentences in cin>>

• You can write sentences in cin.getline

x)

I make some change in your code ,and it 's work OK!
I think it's important that after "cout<<????" statement ADDing a "<<endl",
endl not only make a change line ,
but also "kick off" the content in the BUFFER ' room,
so the content will be immediately send to display .

Code:

---

#include <windows.h>
#include <iostream.h>
#include <stdio.h>
#define WMAX 6
#define PMAX 60
//using namespace std;      //this statement not supportted in my vc++.
inline void start(void)
{
    char wayinput[WMAX];
    char pname[PMAX];
    cout << "What do you want to be called?\n"; 
    //in the end ,must add "<<endl;",if or not , this message dont display!

    cin>>pname;    //instead of "cin.getline (pname, 60);",
                            //I donnt know reason,but it's wrok in my computer!
   
    cout << "\nOk, hello " << pname << ", right now you are in Hilstone Village.";
      //add "<<endl;" in the end.
}

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