Breaking out of a loop

I dont know how to break out of two loops when the number input by the user is found. A user enters a number and it searches the array num[4][8] and when this prints obviously it prints that the number was found or not found 4 times because it only broke the inner loop ONLY when the number has found a match.

Please help! thanks!

Code:

---

void diff()
{
 char ans;
 int s;
 printf("\n\nSearch for a number in the array?");
 fflush(stdin);
 scanf("%c", &ans);
 if(ans == 'y' || ans == 'Y')
 {
  printf("\n\nKey in integer to be searched for:");
  fflush(stdin);
  scanf("%d", &s);
  for(suba = 0; suba < 4; suba++)
  {
  for(subb = 0; subb < 8; subb++)
  {
    if(num[suba][subb] == s)
    {
    printf("\n%d is in the array\n", s);
    break;
    }
    else
    {
    printf("\n%d is not in the array\n", s);
    break;
    }
  }
  }
 }
 if(ans == 'N' || ans == 'n')
 {
  eoj();
 }
}

---

There are two common ways:

Code:

---

/* Set a flag */
int done = 0;

for ( i = 0; i < 4 && !done; i++ ) {
  for ( j = 0; j < 8; j++ ) {
    if ( something ) {
      done = 1;
      break;
    }
    else {
      /* Keep going */
    }
  }
}

---

Code:

---

/* The dreaded goto */
for ( i = 0; i < 4; i++ ) {
  for ( j = 0; j < 8; j++ ) {
    if ( something )
      goto end;
    else {
      /* Keep going */
    }
  }
}
end:

---

There's a third less used way...

Code:

---

for( i = 0; i < foo; i++ )
{
    for( x = 0; x < bar; x++ )
    {
        for( z = 0; z < foo + bar; z++ )
            if( condition )
                exit( 0 );
            else
                dostuff( ";)" );
    }
}

---

Quzah.

I think one of these might do it. I will give them a try and let you know how it goes. Thanks you guys! =)

The exit (0); did it, thanks a lot guys!

I need this to go back to the top and run read() again. I have put them all in one fucntion ebcause its driving me crazy. this assignment never ends. I sure hope this course does! sever e crippling/blinding migraines dont help but I dont question the CAUSE!

Code:

---

void read()
{
 for(suba = 0; suba < 4; suba++)
 {
  for(subb = 0; subb < 8; subb++)
  {
  x = rand()%51;
  num[suba][subb] = x;
  printf("%4d", num[suba][subb]);
  }
  printf("\n");
 }
 printf("\n\nSearch for a number in the array?");
 fflush(stdin);
 scanf("%c", &ans);

 if(ans == 'y' || ans == 'Y')
 {
  printf("\n\nKey in integer to be searched for:");
  fflush(stdin);
  scanf("%d", &s);
  for(suba = 0; suba < 4; suba++)
  {
  for(subb = 0; subb < 8; subb++)
  {
    if(num[suba][subb] == s)
    {
    printf("\n%d is in the array\n\n", s);
    printf("Press enter to continue\n\n");
    fflush(stdin);
    getchar();
    exit(0);
    }
    else
    {
    printf("\n%d is not in the array\n\n", s);
    printf("Press enter to continue\n\n");
    fflush(stdin);
    getchar();
    exit(0);
    }
  }
  }
 }
 if(ans == 'N' || ans == 'n')
 {
  eoj();
 }
}

---

Actually, exit( 0 );, was meant as a joke. It exits the program.

Quzah.

Quote:

---

fflush(stdin);

---

http://faq.cprogramming.com/cgi-bin/...&id=1043284351

I read that. And explained it before. I don't know whether or not I should believe the FAQ. I have no reason to believe its not strapped with more terrorist bombs.

You read it, yet you still use it?

Bah wth, just noticed it didn't convert the URL. sigh