String formatting

char word[30] = "hello||how||are||you||doing||there"


how can i break the string and display the following output ??

hello|
|how|
|are|
|you|
|doing|
|there

Neglecting any invalid input, you could simply traverse the whole string and preint each character 1 by 1. If you encounter a |, print a newline then skip the following character (assuming they always comes in pairs of 2).

Code:

---

char* Pointer = word;
while(*Pointer != '\0')
{
  if(*Pointer == '|')
  {
    printf("\n");
    Pointer++; //Skips extra character
  }
  else
  {
    printf("%c", *Pointer);
  }
  Pointer++;
}

---

Note: Code has not been tested.

Code:

---

int main() {
        char *word = "hello||how||are||you||doing||there";
       
        while (*word != '\0') {
                if (*word != '|') {
                        printf("%c", *word);
                        word++;
                } else if (*word == '|') {
                        printf("%c", *word);
                        word++;
                        printf("\n%c", *word);
                        word++;
                }
        }
                return 0;
}

---

Code:

---

#include <stdio.h>

int main(void)
{
  char word[] = "hello||how||are||you||doing||there";
  char* Pointer = word;
  while(*Pointer != '\0')
    {
      printf("%c%s", *Pointer, *Pointer == '|' && *(Pointer+1) == '|' ? "\n" : "");
      Pointer++;
    }
  return 0;
}

---

Great solution major. Reminds me of a professor in college that took a simple solution to a problem and wrote a small portion of code for it in C.

Each time through he would re-write the code and simplify or concatendate certain parts of the code until he got to only 2 lines of code for a solution that had 10 lines originally.

... or if you can live without the | characters....:

Code:

---

#include <stdio.h>
#include <string.h>

int main(void)
{
  char word[] = "hello||how||are||you||doing||there";
  char *p;
 
  p = strtok (word, "|");
 
  while (p)
  {
    puts (p);
    p = strtok (NULL, "|");
  } 
 
  return(0);
 
}

---