Need serious help on array of structures

I can't figure out how to access data members in an array of structures to store data.

Here is my program:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct drivers_license
{
char lastname[10];
char firstname[10];
int licensenumber[8];
char statecode[2];
struct address;
int height;
char eyecolor[8];
char haircolor[8];
struct vehicle;
char visioncode[10];
int birthdate[3];
int expirationdate[3];
char organdonor[3];
};

struct address
{
int streetnumber[5];
char streetname[10];
int aptnumber[5];
char city[10];
char state[10];
int zipcode[5];
};

struct vehicle
{
char motorcycle;
char automobile;
char schoolbus;
char commericaltruck;
char semitrailer;
};

void records(struct drivers_license record[15]);
void changes(struct drivers_license record[15]);

int main()
{
struct drivers_license record[15];
return 0;
}

//Now this below is what someone else wrote to help and sprintf does not do what exactly I would like to do, I want the character string inputed in but it won't print out, I need someone to show different ways of inputing the character strings in the array of structures

void records(struct drivers_license record[15])
{

sprintf( record[0].lastname, "Smith" );
}

void changes(struct drivers_license *record[15])
{
}

To store a name in your drivers_license structure you would do strcpy(record[0].firstname, "Myname");
This will store myname in the first structure of the array.
When using a pointer you need to use the -> operator instead of the . operator

well what do you want to do? sprintf should work...here's an example of how to do this kinda stuff:

Code:

---

struct info_{
        char name[30];
        int age;
}info[4];

int main(void)
{
        sprintf(info[0]->name,"Jimmy Olsen");
        info[0].age = 23;
        sprintf(info[1]->name,"something");
        info[1].age = 49;
        sprintf(info[2]->name,"something else");
        info[2].age = 63;
        sprintf(info[3]->name,"Joe bob");
        info[3].age = 47;
        sprintf(info[4]->name,"Mary Poppins");
        info[4].age = 10;

        for(int x=0;x<4;x++)
                printf("%s\n%d\n",info[x]->name, info[x].age);

        return 0;
}

---

or you could get the name/age from the user by using...

Code:

---

printf("Enter name: ");
gets(info[x]->name);
printf("enter age: ");
scanf("%d",&info[x].age);

---

that help at all?