strcat - strcpy

Why this code doesn't work?
<code>
char string[10];

strcat( string, "hello" );
puts ( string );
</code>

and why when i write
<code>
char string[10] = "";

strcat( string, "hello" );
puts ( string );
</code>
it will work?

Could you also tell me the difference between char string[10]; and char string[10] = ""; ?

And why this problem won't appear when using strcpy() ????

Mena meny thx - Polor

let me exaggerate, this is a string
char string[10] = ""'
it is because the string is this
"\0", no '\0'
this is not a string,
char string[10];
this is memory allocated for a string.

Quote:

---

Originally posted by Salem
> Could you also tell me the difference between char string[10]; and char string[10] = ""; ?
One is initialised to contain a zero-length string, and the other contains junk which has no defined end ...

---

which as Salem mentioned contains uninitialized data. IOW, whatever happens to be in memory when string[] is created is it's contents, otherwise know as junk.

And by the way, it's [code] not <code>

ok, but what about my other 2 questions?
and what does zero-length string mean?

Thx - Polor

Ok, thanks! I got it now! :)
- Polor